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zheka24 [161]
3 years ago
5

NEED ANSWER ASAP

Chemistry
2 answers:
Oksana_A [137]3 years ago
8 0
I think it is A (10 %)
krek1111 [17]3 years ago
3 0
A. 10% is the answer.
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What is the volume of 4.78g of O2 gas at STP?
My name is Ann [436]

Answer:

Explanation:

The trick here is to realize that if you know the volume of a gas at STP, you can use the fact that

1

mole of any ideal gas occupies

22.7 L

under STP conditions to calculate how many moles of gas you have in your sample.

Under STP conditions:

1 mole of an ideal gas = 22.7 L

−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−

In your case, you know that your sample of gas occupies

2.28 L

under STP conditions, which are currently defined as a pressure of

100 kPa

and a temperature of

0

∘

C

.

This means that your sample will contain

2.28

L

⋅

molar volume of a gas at STP



1 mole gas

22.7

L

=

0.10044 moles gas

Now, the molar mass of the gas is the mass of exactly

1

mole of the gas. In your case, you know that you get

3.78 g

for every

0.10044

moles, which means that you have

1

mole

⋅

3.78 g

0.10044

moles

=

37.6 g

Since this is the mass of

1

mole of gas, you can say that the molar mass of the gas is

molar mass = 37.6 g mol

−

1

−−−−−−−−−−−−−−−−−−−−−−−

8 0
2 years ago
Read 2 more answers
NEED HELP FAST I WILL MARK BRAINLIEST AND THANK YOU AND RATE 5 STARS.
sleet_krkn [62]
Hello there,

All compounds of carbon are made by <span>ionic bonding.

I Hope this helps.

~Jurgen</span>
5 0
3 years ago
Read 2 more answers
Convert 4.0 kilometers 2 meters
Dominik [7]
4 x 1000 so 4 kilometers are equal to 4000 meters
4 0
3 years ago
What phase of matter is oxygen at room temperature
Vedmedyk [2.9K]
Gas

good luck mate :)
8 0
2 years ago
A 20.0 g piece of a metal is heated and place into a calorimeter containing 250.0 g of water initially at 25.0 oC. The final tem
BartSMP [9]

Answer:

Q_{metal} = -6799\,J

Explanation:

By the First Law of Thermodynamics, the piece of metal and water reaches thermal equilibrium when water receives heat from the piece of metal. Then:

Q_{metal} = - Q_{w}

Q_{metal} = m_{w} \cdot c_{p,w}\cdot (T_{1}-T_{2})

Q_{metal} = (250\,g)\cdot \left(4.184\,\frac{J}{g\cdot ^{\textdegree}C} \right)\cdot (25\,^{\textdegree}C - 31.5\,^{\textdegree}C)

Q_{metal} = -6799\,J

6 0
3 years ago
Read 2 more answers
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