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3 years ago

Which one represents a line which is parallel to the line y=-7x-4

Mathematics

1 answer:

Mekhanik [1.2K]3 years ago

3 0

Answer:

Any linear equation of the slope-intercept form y =7x/4+ b will be parallel to y=7x/4, since the slope of 7/4 will be the same for all such lines

Step-by-step explanation:

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35. Sam can join a gym for $25.00 per month or

Natali [406]

Answer:

21 months

Step-by-step explanation:

1 month: $25.00 2 month: $50.00 3 month: $75.00 4 month: $100.00 5 month: $125.00 6 month: $150.00 7 month: $175.00 8 month: $200.00 9 month: $225.00 10 month: $250.00 11 month: $275.00 12 month: $300.00 13 month: $325.00 14 month: $350.00 15 month: $375.00 16 month: $400.00 17 month: $425.00 18 month: $450.00 19 month: $475.00 20 month: $500.00 21 month: $525.00

By the 21st month, Sam would have paid $525 making the flat fee a better choice.

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3 years ago

Can movement of matter cannot occur without energy transfer

Aleks04 [339]

Yes: example-because if u are running u are using energy

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3 years ago

HELP ASAP PLEASE!!!!

polet [3.4K]

Answer:

bqgsdfgsdfghsdfbvcxbxcvb

Step-by-step explanation:

my grandmother told me the answer

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3 years ago

How do I verify #15 using fundamental trig identities?

expeople1 [14]

We start with the more complicated side which is the left side, and show that, on using some trigonometric identities, we will get the term on the right side .

$\frac{sin \theta + tan \theta}{1+cos \theta}$

Using Quotient identity for tangent function, we will get

$\frac{sin \theta+ \frac{sin \theta}{cos \theta}}{1+cos \theta}$

$\frac{sin \theta cos \theta + sin \theta}{cos \theta(1+cos \theta)}$

Taking out sine function from the numerator

$=\frac{sin \theta(1+cos \theta)}{cos \theta(1+cos \theta)}$

Cancelling the common term of numerator and denominator

$=\frac{sin \theta}{cos \theta} = tan \theta$

7 0

3 years ago

Establish for which constants c the following function is a density.

Valentin [98]

By "density" I assume you mean "probability density function". For this to be the case for $f(x)$ , we require

$\displaystyle\int_{-\infty}^\infty f(x)\,\mathrm dx=1$

Since

$f(x)=\begin{cases}cx^{1/2}&\text{for }0$

you have

$\displaystyle\int_{-\infty}^\infty f(x)\,\mathrm dx=\int_0^2cx^{1/2}\,\mathrm dx=\dfrac{2c}3x^{3/2}\bigg|_{x=0}^{x=2}=\dfrac{2^{5/2}c}3=1$

which means

$c=\dfrac3{2^{5/2}}=\dfrac3{4\sqrt2}$

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3 years ago