The days she has recorded: 11 + 10 + 7 + 6 + 3 + 2 = 39
The mode distance (most often): 5 km
Median distance: 6.64 km ~= 6.5 km ~= 7 km by rounding upwards, so 3rd
Cumulative frequency: 11; 21; 28; 34; 37; 39
4s+7a=861
s+a=168
This can be solved using either elimination or substitution. I am going to use substitution.
Solve s+a=168 for s
s=168-a
Replace 168-a for s in 4s+7a=861
4(168-a)+7a=861
672-4a+7a=861
Solve for a
672+3a=861
3a=189
a=63
Substitute 63 for a in s=168-a
s=168-63=105
So, s=105 student tickets and a=63 adult tickets
B. 16 cm
Square both 20 and 12
20x20=400
12x12=144
400-144=256
find the square root of 256
and the square root is 16
so b is 16 cm
Answer:
x=
−399
/75
Explanation:
Step 1:
−34(8x+12)=3(x−3)
(−34)(8x)+(−34)(12)=(3)(x)+(3)(−3)(Distribute)
−272x+−408=3x+−9
−272x−408=3x−9
Step 2:
−272x−408−3x=3x−9−3x
−275x−408=−9
Step 3:
−275x−408+408=−9+408
−275x=399
Step 4:
−275x
−275
=
399
−275