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Mrrafil [7]
3 years ago
14

Over the last three evenings, Ivanna received a total of 116 phone calls at the call center. The third evening, she received 4 t

imes as many calls as the first
evening. The second evening, she received 10 fewer calls than the first evening. How many phone calls did she receive each evening?
Mathematics
1 answer:
KonstantinChe [14]3 years ago
3 0

Answer:

first evening = 21 phone calls

second evening = 11 phone calls

third evening = 84 phone calls

Step-by-step explanation:

Total phone calls = 116

Let

Number of calls in the first evening = x

The second evening = x - 10

The third evening = 4x

Total phone calls = first evening + second evening + third evening

116 = x + (x - 10) + 4x

116 = x + x - 10 + 4x

116 + 10 = 6x

126 = 6x

x = 126 / 6

x = 21 phone calls

Number of calls in the first evening = x

= 21 phone calls

The second evening = x - 10

= 21 - 10

= 11 phone calls

The third evening = 4x

= 4(21)

= 84 phone calls

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so
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the sum is the known+unknwon
sum=76+99+86+x

so
90<span><</span>average and average <span><</span>100
or
90<span><</span>average<span><</span>100


lets say average=a

a=sum/number
a=(76+99+86+x)/4

90<(76+99+86+x)/4<100
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3 years ago
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3 years ago
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3 years ago
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Solve for d. | - 2d|&lt;10
Romashka-Z-Leto [24]

 Your question: Find D in | - 2d|<10

==========================================================

SOLVING....

Solve the absolute value

|−2d| < 10

     =

−2d < 10

    or

−2d > −10

Solve −2d < 10 for D

Divide each side by -2

-2d ÷ -2 < 10 ÷ -2

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Now Solve −2d > −10

Divide each side by -2

-2d ÷ -2 > -10 ÷ -2

d < 5

So D is d < 5  and d > -5

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3 years ago
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