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Mrrafil [7]
3 years ago
14

Over the last three evenings, Ivanna received a total of 116 phone calls at the call center. The third evening, she received 4 t

imes as many calls as the first
evening. The second evening, she received 10 fewer calls than the first evening. How many phone calls did she receive each evening?
Mathematics
1 answer:
KonstantinChe [14]3 years ago
3 0

Answer:

first evening = 21 phone calls

second evening = 11 phone calls

third evening = 84 phone calls

Step-by-step explanation:

Total phone calls = 116

Let

Number of calls in the first evening = x

The second evening = x - 10

The third evening = 4x

Total phone calls = first evening + second evening + third evening

116 = x + (x - 10) + 4x

116 = x + x - 10 + 4x

116 + 10 = 6x

126 = 6x

x = 126 / 6

x = 21 phone calls

Number of calls in the first evening = x

= 21 phone calls

The second evening = x - 10

= 21 - 10

= 11 phone calls

The third evening = 4x

= 4(21)

= 84 phone calls

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alexgriva [62]
<h2>Answer:</h2>

<em>Rounded to the nearest hundredth the volume of the composite figure is:</em>

<em>1308 33 cubic millimeters</em>

<h2>Explanation:</h2>

Hello! I wrote the complete question in a comment above. The volume of a cylinder is defined as:

V_{c}=\pi r^2 h \\ \\ r:radius \\ \\ h:height

While the volume of half a sphere is:

V_{hs}=\frac{2}{3}\pi r^3

Since we have 2 half spheres, then the volume of these is the same as the volume of a sphere:

V_{s}=\frac{4}{3}\pi r^3

Then, the composite figure is:

V=\pi r^2 h +\frac{4}{3}\pi r^3 \\ \\ V=\pi r^2(h+\frac{4}{3}r)

The radius of the cylinder is the same of the radius of each half sphere. So:

r=5mm \\ \\ h=10mm \\ \\ \\ V=(3.14) (5)^2((10)+\frac{4}{3}(5)) \\ \\ V=25(3.14)(10+\frac{20}{3}) \\ \\ \boxed{V\approx 1308.33mm^3}

7 0
3 years ago
A^4 + 2b OVER a; if a =3 and b = 12
Tems11 [23]

Answer:

105

Step-by-step explanation:

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3 ⁴ = 81

2 x 12 = 24

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81 + 24

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6 0
3 years ago
Please help? Thank you
Alex17521 [72]

Answer:

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4 0
3 years ago
A standard six sided dice is rolled. What is te probability of rolling a 3 OR a 5
Vikki [24]

Answer:

1/3

Step-by-step explanation:

Rolling a die has the possible outcomes of 1,2,3,4,5,6 = 6 total

P(3 or 5) = number of  3 or 5's / total

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5 0
3 years ago
Read 2 more answers
What is the sum or difference?
dlinn [17]
1. Ans: Option (B) -6x^4

Explanation:
Given: 2x^4 - 8x^4
Take the common out:
=> x^4(2 - 8)

Hence: => [tex]-6x^4[/tex] (Option B)

2. Ans: Option (D) -3y^5

Explanation:
Given: 6y^5 - 9y^5
Take the common term(s) out:
=> y^5(6-9)

Hence: => -3y^5 (Option D)

3. Ans: Option (B) 9x^2 - 12x + 6<span> quadratic trinomial 

Explanation:
</span>Given: 6 - 12x + 13x^2 - 4x^2

The standard form of polynomial function must have the highest powered value at the start, then the second highest and so on.

=> 
13x^2 - 4x^2 - 12x + 6
=> 9x^2 - 12x + 6 (Option B)

4. Ans: Option (C) 7.3x^2 + 0.8x + 1.3

Explanation:
In order to find the total number of C<span>ommon and Endler's guppies, you need to add both Common and Endler's guppies' polynomials, as follows:

</span>Common guppies: 3.1x^2 +6.0x + 0.3<span>
Endler's guppies:   </span>4.2x^2 - 5.2x + 1.0
(add both)
-----------------------------------------------------------------
Total number:          7.3x^2 +0.8x + 1.3
-----------------------------------------------------------------
Hence the ans is Option(C) 7.3x^2 + 0.8x + 1.3

5. Ans: Option (D) 2x^2(133 - 18 \pi )

Explanation:
First let's find the total area of the yard:
Total Area of the Yard = 14x * 19x = 266x^2

Now the area of the circular fountain:
Area of the Circular Fountain = \pi r^2
Since, r=6x
Therefore,
Area of the Circular Fountain = \pi (6x)^2 = 36 \pi x^2

Now the final Area of the yard would be:
Final area of the Yard = Total Area of the Yard - Area of the Circular Fountain
Final area of the Yard = 266x^2 - 36 \pi x^2
=> Final area of the Yard = 2x^2(133 - 18 \pi) (Option D)

6. Ans: Option (A) 56x^2

Explanation:
First let's find the total area of the lot:
Total Area of the lot= 6x * 10x = 60x^2

Now the area of the stadium:
Area of the stadium = 1x * 4x = 4x^2

Now the final Area of the lot would be:
Final area of the lot= Total Area of the lot - Area of the stadium
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=> Final area of the lot = 56x^2 (Option A)

-i
4 0
3 years ago
Read 2 more answers
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