Question

Identify the zeros of f(x)=(x-7)(x+4)(3x-2)

Answer 1

To find the zero you must set each factor equal to zero and solve for for x like so...

Factor (x - 7)

x - 7 = 0

x = 7

Factor (x + 4)

x + 4 = 0

x = -4

Factor (3x - 2)

3x - 2 = 0

3x = 2

x = $\frac{2}{3}$

All the zeros are:

-4, $\frac{2}{3}$, 7

Hope this helped!

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