Answer:
Step-by-step explanation:
1
Given x³, we can write the equivalent expression -----------
x^(-3)
1
Given y^(-4) we can rewrite this as ----------
y^4
Here we're applying the "rule of negative exponents."
Given that In 3 years, Dianna will be 4 times as old as she was 33 years ago, her present age is 45.
<h3>How old is Dianna now?</h3>
Given that, in 3 years, Dianna will be 4 times as old as she was 33 years ago.
Let x represent the age of Dianna presently.
Dianna's age in 3 years time will be: x + 3
Dianna's age 33 years ago is: x - 33
Since in 3 years, she will be 4 times as old as she was 33 years ago.
x + 3 = 4( x - 33 )
We solve for x
x + 3 = 4x - 132
3 + 132 = 4x - x
135 = 3x
x = 135/3
x = 45
Given that In 3 years, Dianna will be 4 times as old as she was 33 years ago, her present age is 45.
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First put the words in an algebraic format or a model. D = 3.5(√H). Now determine what the question is asking. It's height. Plug in the value of D. Distance is 35 km.
35 = 3.5(√H) We want to get H by itself. First thing to get away from it is 3.5. So divide 35 by 3.5 And 3.5(√h) by 3.5.
10 = √H To get rid of √ do the opposite raise to the power of 2
10² = (√H)²
100 = H
You must be 100 kilometers above ground to see 35 kilometers
Answer: Check
12^10 × 12^(-2) = 12^(10 - 2) = 12^8
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Second option : ---
3^2 × 4^6 = 3^2 × 4^2 × 4^4 = 12^2 × 4^4
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Third option : ---
(12^8)^0 = 12^(8 × 0) = 12^0 = 1
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4th option : Check
12^10 / 12^2 = 12^10 × 12^(-2) = 12^(10 - 2)
= 12^8
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5th option : Check
2^8 × 6^8 = ( 2 × 6 )^8 = 12^8
Step-by-step explanation: