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3 years ago

2. The length of one diagonal of a rhombus is 8 cm. The area of the

Mathematics

1 answer:

Rina8888 [55]3 years ago

6 0

Answer:

18.

Step-by-step explanation:

If the equation for the area of a rhombus is A=pq÷2, then you take 72, and you multiply it by 2, which gets you 144, then you simply take 144 and divide it by 8, which gets you 18. And then once you've done all that, you can simply check your math by plugging the numbers into the equation formula I've provided above. In case you're unsure of what it is, here it is again, A=pq÷2.

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If you have 1.234545 davidi by 50=

Umnica [9.8K]

0.0246909 hope this helps love ❤️

5 0

3 years ago

Read 2 more answers

Answer both question for 20 points and brainliest

Dmitrij [34]

Answer:

1 - c

2 - A

Step-by-step explanation:

Hey There!

So for the first one we are given the dimensions of a rectangular prism and they want us to find the volume

Remember to find the volume we use the equation

V = length x width x height

so we just plug in the values

v = 2.6 x 2.1 x 3.9 = 21.294

the closest is 20 so C is your answer

For the second one we are given a triangular prism

and they want us to find the volume

$V=\frac{1}{2} bhl$

b = base (10.3)

l = length (4)

h = height (7)

7x4=28

28x10.3=288.4

then we divide by 2

288.4/2=144.2

so your selected answer is correct

4 0

3 years ago

A farmer has 520 feet of fencing to construct a rectangular pen up against the straight side of a barn, using the barn for one s

Setler [38]

Answer:

$310\text{ feet and }210\text{ feet}$

Step-by-step explanation:

GIVEN: A farmer has $520 \text{ feet}$ of fencing to construct a rectangular pen up against the straight side of a barn, using the barn for one side of the pen. The length of the barn is $310 \text{ feet}$ .

TO FIND: Determine the dimensions of the rectangle of maximum area that can be enclosed under these conditions.

SOLUTION:

Let the length of rectangle be $x$ and $y$

perimeter of rectangular pen $=2(x+y)=520\text{ feet}$

$x+y=260$

$y=260-x$

area of rectangular pen $=\text{length}\times\text{width}$

$=xy$

putting value of $y$

$=x(260-x)$

$=260x-x^2$

to maximize $\frac{d \text{(area)}}{dx}=0$

$260-2x=0$

$x=130\text{ feet}$

$y=390\text{ feet}$

but the dimensions must be lesser or equal to than that of barn.

therefore maximum length rectangular pen $=310\text{ feet}$

width of rectangular pen $=210\text{ feet}$

Maximum area of rectangular pen $=310\times210=65100\text{ feet}^2$

Hence maximum area of rectangular pen is $65100\text{ feet}^2$ and dimensions are $310\text{ feet and }210\text{ feet}$

5 0

3 years ago

Find x. Round to the nearest tenth if needed.

alexdok [17]

Answer:

x = 16

Step-by-step explanation:

Use that the addition of all internal angles of a triangle must add up to 180, and the fact that the two given triangles are similar:

51 + 65 + 4 x = 180

combine and solve for "x"

116 + 4 x = 180

4 x = 180 - 116

4 x = 64

x = 64 / 4

x = 16

5 0

3 years ago

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17. What is the area of the figure below?

Sidana [21]

If length of rectangle is 8 cm, breadth is 4 cm, side of square is 3 cm, base of triangle is 3 cm, then the area of figure will be 48.5 $cm^{2}$ .

Given that length of rectangle is 8 cm, Breadth of rectangle is 4 cm,side of square is 3 cm,base of right angled triangle is 3 cm,height of triangle is 5 cm.

Area of figure=Area of rectangle+Area of square+Area of triangle

Area of rectangle=length*breadth

Area of square=Side*Side

Area of triangle=1/2 *Base*Height

Area of figure=8*4+3*3+1/2 *3*5

=32+9+1/2 *15

=41+15/2

=(82+15)/2

=97/2

=48.5 $cm^{2}$

Hence if length of rectangle is 8 cm, breadth is 4 cm, side of square is 3 cm, base of triangle is 3 cm, then the area of figure will be 48.5 $cm^{2}$ .

Learn more about area at brainly.com/question/25292087

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7 0

1 year ago