Answer:
The trial provides enough evidence that the probability of obtaining heads is less than 0.50 and that the coin is unfair.
Step-by-step explanation:
The explanation is in the picture
76 is 40% of what number?
1 answer:
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The Least Common Multiple is used to add fractions with unlike denominators:
Three things can happen:
1/3 + 1/7 - the LCM is the product of the denominators (in this case 21)
2/8 + 3/16 - the LCM is the greater denominator (in this case 16)
2/9 + 5/6 - the LCM is lower than the product of the denominators (in this case it is 18)
The Greatest Common Factor is used to reduce fractions quickly:
÷ 
= 
By using the GCF -in this case 24, I reduced the fraction in a single step.
If I kept dividing by 2/2 (not the GCF), it would take much longer:
48/72 = 24/36 = 12/18 = 6/9 and then I would still have to divide 6/9 by 3/3 to get 2/3
Three things can happen:
1/3 + 1/7 - the LCM is the product of the denominators (in this case 21)
2/8 + 3/16 - the LCM is the greater denominator (in this case 16)
2/9 + 5/6 - the LCM is lower than the product of the denominators (in this case it is 18)
The Greatest Common Factor is used to reduce fractions quickly:
By using the GCF -in this case 24, I reduced the fraction in a single step.
If I kept dividing by 2/2 (not the GCF), it would take much longer:
48/72 = 24/36 = 12/18 = 6/9 and then I would still have to divide 6/9 by 3/3 to get 2/3
Answer:
<em>Money in her purse is Rs. 500.</em>
<em></em>
Step-by-step explanation:
Let the money in her purse = Rs.
Let the money in her Money box = Rs.
As per question statement,
- Double the money in her purse (i.e.
) and add it to the amount in money box, she gets Rs. 1700.
........ (1)
- Triple the money in her purse (i.e.
) and add it to amount in money box (
), she gets Rs. 2200.
....... (2)
<u>To find: </u>Money in her purse = ? i.e.
Let us solve for using the two linear equations.
We can use substitution method here i.e. find value of one variable from one equation and then substitute that value in other equation.
Using equation (1), we get the value of as follows:
Now, let us put this value of y in equation (2) to find the value of :
<em>Money in her purse is Rs. 500.</em>