What is the next fraction in this sequence? Simplify your answer.

The average length of a ladybug can range from 0.08 to 0.4 inches. find two lengths that are within the given span. write them a

inysia [295]

<u>Answer</u>

1) 11/100

2) 1/10

<u>Experience</u>

There are infinate fractions between any two integers. The same way there are somany numbers between 0.08 and 0.4.

Examples are 0.09, 0.10, 0.11. 0.12,0.2,0.3, 0.35 and many more.

I will just pick two of them and write them as a fraction.

1) 0.11 = 11/100

2) 0.20 = 20/200

= 2/20

= 1/10

3 0

3 years ago

Read 2 more answers

Solve y = 4x + 12, using the x-values, 3, 5, and 8. Which of the following T-tables represents the ordered pairs?

SCORPION-xisa [38]

You plug in each of the 3 numbers as x so the table should have 3,5,8 as x and whatever you get for y for each one is your answer. I saw that you posted this 2 days ago, so you probably don't need help XD

4 0

2 years ago

Read 2 more answers

Travis milks his cows each morning. He has never gotten fewer than 3 gallons of milk; however, he always gets fewer than 9 gallo

k0ka [10]

That’s the question?

5 0

2 years ago

How to solve for 3x - 24 = 81

VladimirAG [237]

Answer:

35

Step-by-step explanation:

3x=81+24

3x=105

x=35

6 0

2 years ago

Read 2 more answers

A gas is said to be compressed adiabatically if there is no gain or loss of heat. When such a gas is diatomic (has two atoms per

Tems11 [23]

Answer:

The pressure is changing at $\frac{dP}{dt}=3.68$

Step-by-step explanation:

Suppose we have two quantities, which are connected to each other and both changing with time. A related rate problem is a problem in which we know the rate of change of one of the quantities and want to find the rate of change of the other quantity.

We know that the volume is decreasing at the rate of $\frac{dV}{dt}=-4 \:{\frac{cm^3}{min}}$ and we want to find at what rate is the pressure changing.

The equation that model this situation is

$PV^{1.4}=k$

Differentiate both sides with respect to time t.

$\frac{d}{dt}(PV^{1.4})= \frac{d}{dt}k\\$

The Product rule tells us how to differentiate expressions that are the product of two other, more basic, expressions:

$\frac{d}{{dx}}\left( {f\left( x \right)g\left( x \right)} \right) = f\left( x \right)\frac{d}{{dx}}g\left( x \right) + \frac{d}{{dx}}f\left( x \right)g\left( x \right)$

Apply this rule to our expression we get

$V^{1.4}\cdot \frac{dP}{dt}+1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}=0$

Solve for $\frac{dP}{dt}$

$V^{1.4}\cdot \frac{dP}{dt}=-1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}\\\\\frac{dP}{dt}=\frac{-1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}}{V^{1.4}} \\\\\frac{dP}{dt}=\frac{-1.4\cdot P \cdot \frac{dV}{dt}}{V}}$

when P = 23 kg/cm2, V = 35 cm3, and $\frac{dV}{dt}=-4 \:{\frac{cm^3}{min}}$ this becomes

$\frac{dP}{dt}=\frac{-1.4\cdot P \cdot \frac{dV}{dt}}{V}}\\\\\frac{dP}{dt}=\frac{-1.4\cdot 23 \cdot -4}{35}}\\\\\frac{dP}{dt}=3.68$

The pressure is changing at $\frac{dP}{dt}=3.68$ .

7 0

3 years ago

What is the next fraction in this sequence? Simplify your answer.​

What is the next fraction in this sequence? Simplify your answer.