Answer:
0.483
Explanation:
The given population is in Hardy-Weinberg equilibrium. If the gene has two alleles, the sum total of the frequencies of these two alleles will be one.
Therefore, the total of the frequency of allele B and frequency of allele b will be 1. f(B) + f(b)=1
If the frequency of allele "B" is 0.59, then the frequency of allele "b" will be=1-0.59= 0.41
The frequency of heterozygous genotype in the population= 2pq
p= frequency of the dominant allele
q= frequency of the recessive allele
So, 2pq= 2 x 0.59 x 0.41 = 0.483
In my opinion, it would be C!
please let me know if this is correct!
The answer is C) transmit genetic information
<span>Pigeons learn to flap their wings to avoid shock more easily than they learn to peck a disk to avoid shock. they learn to flap their wings to obtain food less easily than they learn to peck a disk to obtain food.
That's what'd I'd assume the answer would be.</span>
Answer: False
Hope this helps b
