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riadik2000 [5.3K]
3 years ago
7

The scale shows both percentages and decimals.

Mathematics
2 answers:
babymother [125]3 years ago
5 0

Answer:

0.9

0.07

Step-by-step explanation:

please like..... ......

soldier1979 [14.2K]3 years ago
3 0
0.9 and 0.07
hope it helps
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Suppose we are interested in bidding on a piece of land and we know one other bidder is interested. The seller announced that th
IgorLugansk [536]

Answer:

a) 0.32 = 32% probability that your bid will be accepted

b) 0.72 = 72% probability that your bid will be accepted

c) An amount in excess of $15,400.

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value X lower than x is given by the following formula.

P(X \leq x) = \frac{x - a}{b-a}

Assume that the competitor's bid x is a random variable that is uniformly distributed between $10,400 and $15,400.

This means that a = 10400, b = 15400

a. Suppose you bid $12,000. What is the probability that your bid will be accepted (to 2 decimals)?

You will win if the competitor bids less than 12000. So

P(X \leq 12000) = \frac{12000 - 10400}{15400 - 10400} = 0.32

0.32 = 32% probability that your bid will be accepted

b. Suppose you bid $14,000. What is the probability that your bid will be accepted?

You will win if the competitor bids less than 14000. So

P(X \leq 14000) = \frac{14000 - 10400}{15400 - 10400} = 0.72

0.72 = 72% probability that your bid will be accepted

c. What amount should you bid to maximize the probability that you get the property (in dollars)?

His bid is uniformly distributed between $10,400 and $15,400.

So, to maximize the probability that you get the property, you should bid an amount in excess of $15,400.

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Number one is -6 and 10
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Determine the median of 4 6 8 10 15 20 21
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i think its 10

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4 6 8 10 15 20 21

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