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spin [16.1K]
3 years ago
12

The trapezoid did a reflect transformation

Mathematics
1 answer:
photoshop1234 [79]3 years ago
6 0

Answer:

point E would go from (2,-4) to (-2,-4)

Step-by-step explanation:

your question was...

The trapezoid did a reflect transformation

1 point

Triangle EFG is located at: E (2,-4), F (2,0), and G (8,0). Where will point E'

be located if the triangle is reflected in the y-axis? *

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Yolanda owns 4 rabbits. She expects the number of rabbits to double every year.
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R=f(y) --> R is a function of y.
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Note that when:

y=0, R=4 ---> Point: (0, 4)

y=1, R=8 ---> Point (1, 8)

y=2, R=16 ---> Point (2, 16)

y=3, R=32 ---> Point (3, 32)

y=4, R=64 ---> Point (4, 64)

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So the equation you want is going to form a curved graph.

That equation is:

R={ 2 }^{ y+2 }

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Prove algebraically that the sum of the squares of two consecutive intgers is always an odd number
musickatia [10]

Answer:

See below.

Step-by-step explanation:

Let's let our first integer be n.

Then, our second, consecutive integer must be (n+1).

We want to prove that the sum of the square of two consecutive integers is always odd.

So, let's square our two expressions and add them up:

(n)^2+(n+1)^2

Square. Use the perfect square trinomial pattern. So:

=n^2+(n^2+2n+1)

Combine like terms:

=2n^2+2n+1

Notice that the first term 2n² has a 2 in front. Anything multiplied by 2 is even. So, regardless of what integer n is, 2n² is <em>always</em> even.

Our second term 2n also has a 2 in front. So, whatever n is, 2n is also <em>always</em> even.

So far, 2n² and 2n are both even. Therefore, the sum of 2n² and 2n is <em>also </em>even.

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