Can y’all help with this question plz

Mathematics

1 answer:

den301095 [7]2 years ago

4 0

Pi x diameter = 14pi or 43.99 in.

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How many solutions does this problem have <br> Y=-2x -4<br> Y= 3x plus 3

S_A_V [24]

Answer:

There is one possible solution

Step-by-step explanation:

Here, we want to get the number of solutions

We can proceed to solve the equation

we have two y values so we can directly equate the x parts

-2x - 4 = 3x + 3

3x + 2x = -3-4

5x = -7

x = -7/5

To get y, we substitute

We can only get one value of y too

So we have a point (x,y) as the solution to the system of equations

7 0

2 years ago

What is the answer to number 9?

Lelu [443]

NAP = 180 - NAC - PAT = 180 - 61 - 46 = 119 - 46 = 73 degrees

6 0

2 years ago

What is the side length of the largest square that can fit into a circle with a radius of 5 units?

Mariana [72]

So 1st consider that it's a square! That's very important. So for a square, all 4 sides are equal.

And now considering that the given information is the diameter. So any angle made at the circle extended from the 2 points of diameter gives an angle of 90°

Now consider one triangle. So we already know that 2 sides of the triangle are equal (because they are 2 sides of a square) , has a side of 10 (diameter) and and angle of 90°. So remaining 2 angles are 45°

Now solve it by applying

$\sin(45) \: \: \: \: = x \div 10 \\ (1 \div \sqrt{2} ) = (x \div 10) \\ 10 \div \sqrt{2} \: = x$

5 0

3 years ago

Can y'all help me with all of them plz

Elena-2011 [213]

10. 150
11. 1250
12. 105
13. 158000
15. B

6 0

2 years ago

Write the complex number -2+2i in polar form

FromTheMoon [43]

For polar form you need to find the modulus (length of the vector) and the argument (angle of the vector) and present in form rcis(Arg) or re^Argi

start with the modulus r=sqrt(a^2 +b^2)
=sqrt(-2^2 +2^2)
= sqrt(4+4)
=sqrt(8)
=2sqrt(2)

next the argument, firstly arg=tan(b/a)
= tan(2/2)
=tan(1)
=pi/4 . (exact values table)
Now consider the quadrant the complex number is in, as it is (-2,2) it is in the second quadrant and as such your Arg value is:
Arg=pi-arg
= pi-pi/4
= 3pi/4

add it all together and your complex number in polar form is:
2sqrt2cis(3pi/4)

note: cis is short hand for cos(x)+isin(x), it is possible your tutor would rather you use the complex exponential form which is simply re^Argi and your answer would look like:
2sqrt2e^(3pi/4)i

Also notice the difference between arg and Arg as this often slips students up and always present Arg in prinicple argument form ie -pi<Arg<pi

Hopefully this has been clear enough and good luck

8 0

2 years ago