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kaheart [24]
2 years ago
9

У

Mathematics
1 answer:
denis23 [38]2 years ago
6 0

Answer:

3y5432 -2123466

Step-by-step explanation:

that is the answer simplified but I don't know what you're asking for

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joseph and patrick purchase school supplies in the book store. Joseph purchases four notebooks and three pens for $10.65. Patric
natali 33 [55]

I think it is going to be 3.55 for each notebook and 1.9 for each pen

6 0
3 years ago
Find the sum of measures of the interior angles of the given figure
Kitty [74]
The answer for this question is 1080
5 0
3 years ago
Can somebody help me with this?
icang [17]

We are given polynomial: 5x^3+8x^2-7x-6.

We need to explain why the binomial (x + 2) IS a factor of this polynomial expression and  why the binomial (x + 1) IS NOT a factor of this polynomial expression.

Let us set first factor equal to 0 and solve for x.

x+2=0

x=-2.

Plugging x=-2 in given polynomial, we get

5(-2)^3+8(-2)^2-7(-2)-6 = 5(-8) +8(4)+14-6

= -40 +32+14-6

=0

<em>Because x=-2 gives 0 on plugging in given polynomial, so it's factor of given polynomial expression.</em>

Now, let us check second factor x+1=0

x=-1.

Plugging x=-1 in given polynomial, we get

5(-1)^3+8(-1)^2-7(-1)-6 = 5(-1) +8(1)+7-6

=-5+8+7-6.

= -4.

<em>Because x=-1 doesn't gives 0 on plugging in given polynomial, so it's not a factor of given polynomial expression.</em>

7 0
3 years ago
It takes Julie 75 minutes to read 60 pages. 
Montano1993 [528]
A) 5/4
b)75:60  525:350. It will take 525 min. to read the entire book
c) 8 hours and 75 min.
3 0
3 years ago
Read 2 more answers
Write 11 k-6 (2k+5)in expanded form and find the sum
marshall27 [118]

Answer:

Option B

Step-by-step explanation:

Expression representing the series is,

\sum_{k=6}^{11}(2k+5)

Here, k = Number of terms

By placing k = 6, 7, 8, 9, 10, 11 in the expression we can get the terms of the series.

For k = 6,

(2k + 5) = 2(6) + 5

            = 17

For k = 7,

(2k + 5) = 2(7) + 5

             = 19

For k = 8,

(2k + 5) = 2(8) + 5

            = 21

For k = 9,

(2k + 5) = 2(9) + 5

            = 23

For k = 10,

0(2k + 5) = 2(10) + 5

            = 25

For k = 11,

(2k + 5) = 2(11) + 5

            = 27

Therefore, expanded form will be,

17, 19, 21, 23, 25, 27

There, is a common difference in each successive to previous term,

d = 19 - 17

d = 2

Number of terms 'n' = 6

First term = 17

Sum of an arithmetic sequence is given by,

S=\frac{n}{2}[2a+(n-1)d]

Therefore, sum of the given sequence will be,

S=\frac{6}{2}[2(17)+(6-1)2]

   = 3(34 + 10)

S = 132

Option B will be the correct option.

4 0
3 years ago
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