All categories

3 years ago

Evaluate the summation of negative 5 n minus 1, from n equals 3 to 12..

Mathematics

1 answer:

NARA [144]3 years ago

5 0

The summation of negative 5 n minus 1, from n equals 3 to 12 can be expressed as

n = 3/12

substitute the value of n to the equatio

-5n – 1

-5( 3/12 ) -1

-9/4

You might be interested in

2t+8 > -4 (t+1) THE > HAS A LIL LINE UNDER IT :) > = ____ _

lara31 [8.8K]

2t + 8 ≥ -4(t+1)

PEMDAS

2t + 8 ≥ -4t - 4

2t + 12 ≥ -4t

12 ≥ -6t

-2 ≤ t

7 0

3 years ago

Calculate the final displacement from 0 if an object first

8_murik_8 [283]

Answer:

final displacement = - 3cm +5cm = + 2 cm

ie 2 cm towards right

6 0

3 years ago

Find the sum of 16+22+28+...+112

Elodia [21]

Im not 100 percent positive that this is correct but I think the answer is
184

6 0

3 years ago

9 x 5 - 9 im give brainlists

Alenkinab [10]

Answer:

9 x 5 - 9 = 36

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Differentiating a Logarithmic Function In Exercise, find the derivative of the function.

sp2606 [1]

Answer:

$\dfrac{d(f(x))}{dx} = \dfrac{2}{x}$

Step-by-step explanation:

We are given the following function in the question:

$f(x) = \ln (3x^2)$

We have to derivate the given function.

Formula:

$\dfrac{d(\ln x)}{dx} = \dfrac{1}{x}\\\\\dfrac{d(x^n)}{dx} = nx^{n-1}$

The derivation takes place in the following manner

$f(x) = \ln (3x^2)\\\\\dfrac{d(f(x))}{dx} = \displaystyle\frac{d(\ln(3x^2))}{dx}\\\\=\frac{1}{3x^2}\times \frac{d(3x^2)}{dx}\\\\= \frac{1}{3x^2}\times (6x)\\\\=\frac{6x}{3x^2}\\\\=\frac{2}{x}$

$\dfrac{d(f(x))}{dx} = \dfrac{2}{x}$

5 0

2 years ago