Refer to the diagram shown below.
When x = 30 ft, the cable is at 15 ft, therefore y(30) = 15.
That is,
a(30 - h)² + k = 15 (1)
Also, because the distance between the supports is 90 ft, therefore
y(0) = 6 ft, and y(90) = 6 ft
That is,
a(-h)² + k = 6 (2)
a(90 - h)² + k = 6 (3)
From (2) and (3), obtain
a(90 - h)² = ah²
90² - 180h + h² = h²
180h = 90²
h = 45 ft.
From (1) and (2), obtain
225a + k = 15
2025a + k = 6
Therefore
1800a = -9
a = - 0.005
k = 15 - 225(-0.005) = 16.125 ft
Answer:
The equation for the cable is
y = - 0.005(x - 45)² + 16.125
A graph of the solution verifies that the solution is correct.
A parallelogram is a quadrilateral<span> or four-sided figure in which the </span>opposite sides are parallel. <span> A rhombus, on the other hand, may be defined as an equilateral parallelogram.</span>
Answer:
-4v5
Step-by-step explanation:
just a guess
The coefficient, 0.25, of the expression represents the late fee for every day the book was overdue.
And the constant, 2, represents the fixed rental fee.
The variable, x, represents the number of days Joseph had the book for.
Hope this helps :)