yes, it does not matter if the y is at the beginning or at the end. However, most teachers usually prefer to have the y at the beginning as it is easier to read.
Answer:
y = -1
Step-by-step explanation:
hopefully it helped
![\sqrt[3]{\dfrac{-27}{125}} = -\sqrt[3]{\left(\dfrac{3}{5}\right)^{3}}=\dfrac{-3}{5}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%5Cdfrac%7B-27%7D%7B125%7D%7D%20%3D%20-%5Csqrt%5B3%5D%7B%5Cleft%28%5Cdfrac%7B3%7D%7B5%7D%5Cright%29%5E%7B3%7D%7D%3D%5Cdfrac%7B-3%7D%7B5%7D)
The appropriate choice appears to be ...
B. -3/5
Answer:
{3-i, 3+ i}
Step-by-step explanation:
hello : the equation is : x²-6x+10 =0
because : (3+i)²-6(3+i)+10 = 9+6i+i²-18-6i+10 =9+6i-1-18-6i+10 =0...right
same method for 3-i... (all quadratic equation have two conjugate solution)
Answer:
5
Step-by-step explanation:
6/2 = 3
because the triangle is halved
use pythagorus 3²+4²=25
√25 = 5
so x=5
