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2 years ago

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The value of y varies directly with x, when y = 36, and x = 9. What is the equation for the relationship? [Do not put any space

in your equation]

2 answers:

Margaret [11]2 years ago

4 0

I will not help you for not using manners!! person above me is right :)

djverab [1.8K]2 years ago

3 0

Answer:

$y=kx\\6=k9\\\frac{6}{9}=k\\\frac{2}{3}=k$

Step-by-step explanation:

im sry if this is incorrect but this is all i could make out of it :(

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What is the area of this figure?

NARA [144]

Answer:

through lengthy mafs, your answer should be <u>307 mi (wrong somehow)</u>

Step-by-step explanation:

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2 years ago

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The number of Proper subsets of a set with m element

bazaltina [42]

Answer:

In general, number of proper subsets of a given set = 2m - 1, where m is the number of elements.

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2 years ago

Please help me with this please and thank you

Ierofanga [76]

Step-by-step explanation:

a geometric sequence means that every term is created by multiplying the previous term by a certain constant factor. this factor is called the "common ratio".

so,

6×r = 18

r = 18/6 = 3

and a quick check tells us this works also for the next terms (18×3 = 54, 54×3 = 162), so it is indeed a geometric sequence with common ratio 3.

a0 = 6

a1 = a0 × 3 = 6×3 = 18

a2 = a1 × 3 = a0 × 3×3 = 6×3² = 54

an = a0 × 3^n = 6 × 3^n

so,

f(x) = 6×3^x, x is integer, x >=0

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2 years ago

PLS HELP I WILL GIVE 15 POINTS OR MORE PLS NO SPAMMING PLS

Blizzard [7]

B,D,F / I’m pretty sure I did this not to long ago

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3 years ago

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PLS PLS HELP, I DONT WANT TO FAIL!!

Flura [38]

Answer:

2.0 seconds

Step-by-step explanation:

<u>Given quadratic functions</u>:

$\begin{cases}y=-7x^2+26x+3\\y=-6x^2 +23x+5\end{cases}$

To find the time, in seconds, that the balloons collided at the highest point, <u>substitute</u> one equation into the other equation and rearrange to <u>equal zero</u>:

$\begin{aligned}-6x^2+23x+5 & = -7x^2+26x+3\\-6x^2+23x+5+7x^2 & = -7x^2+26x+3+7x^2\\x^2+23x+5 & = 26x+3\\x^2+23x+5-26x & = 26x+3-26x\\x^2-3x+5& = 3\\x^2-3x+5-3& = 3-3\\x^2-3x+2& = 0\end{aligned}$

<u>Factor</u> the quadratic:

$\begin{aligned}x^2-3x+2 & = 0\\x^2-2x-x+2 & = 0\\x(x-2)-1(x-2) & = 0\\(x-1)(x-2) & = 0\\\end{aligned}$

Apply the <u>zero-product property</u> to solve for x:

$\implies (x-1)=0 \implies x=1$

$\implies (x-2)=0 \implies x=2$

Therefore, the balloons collided at 1 second and 2 seconds.

To find at which time the highest point of collision occured, substitute both values of x into one of the functions:

$f(1)=-6(1)^2 +23(1)+5=22$

$f(2)=-6(2)^2 +23(2)+5=27$

Therefore, the time, in seconds, that the balloons collided at the highest point is 2.0 seconds.

Learn more about quadratic systems of equations here:

brainly.com/question/27930827

8 0

1 year ago

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