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3 years ago

PLEASE HELP, TY IF YOU ANSER:)<3

Mathematics

1 answer:

Taya2010 [7]3 years ago

6 0

X. . X. X. X. X. X x x x x. X x x x. X x. X x x

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Which expression show the number multiplied for t

jek_recluse [69]

Make the question more clear i cant understand it :/ include all the information from the actual question to get the best answer.

8 0

3 years ago

(2x+3y+4z)(4x^2+9y^2+16z^2-6xy-12yz-8zx)

erma4kov [3.2K]

1.1 Factoring: 4x2+9y2+16z2-6xy-12yz-8xz

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1: -6xy-12yz
Group 2: 16z2-8xz
Group 3: 4x2+9y2

Pull out from each group separately :

Group 1: (x+2z) • (-6y)
Group 2: (x-2z) • (-8z)
Group 3: (4x2+9y2) • (1)

Looking for common sub-expressions :

Group 1: (x+2z) • (-6y)
Group 3: (4x2+9y2) • (1)
Group 2: (x-2z) • (-8z)

6 0

3 years ago

1. A third-grade class needs five leaves each day to feed its two caterpillars. How many leaves would they need each day to feed

Kay [80]

Answer:

17 leaves

Step-by-step explanation:

5 0

3 years ago

The coffee cups can hold 7/9 of a pint of liquid. If Emily puts 2/3 of s pint of coffee into a cup, how much milk can a customer

Bezzdna [24]

1/9 pints of milk can be added by a customer

Step-by-step explanation:

We have to subtract simple fractions to find the amount of milk that can be added to a cup of coffee

Given

Total Capacity of a cup = 7/9 pints

Coffee to be added in a cup = 2/3 pints

So in order to find the amount of milk that can be added we have to subtract the amount of coffee from the total capacity of cup.

So,

$Amount\ of\ milk = \frac{7}{9} - \frac{2}{3}\\=\frac{7-6}{9} = \frac{1}{9}$

Hence,

1/9 pints of milk can be added by a customer

Keywords: Fractions, addition

Learn more about fractions at:

#LearnwithBrainly

7 0

3 years ago

Find the exact value of the following limit: lim x approaches 0 e^6x... check photo above.

horrorfan [7]

Substituting <em>x</em> = 0 directly gives the indeterminate form 0/0, so you can use l'Hopital's rule (and you'll have to do that twice):

$\displaystyle\lim_{x\to0}\frac{e^{6x}-6x-1}{x^2}=\lim_{x\to0}\frac{6e^{6x}-6}{2x}=\lim_{x\to0}\frac{36e^{6x}}2$

The limand is continuous everywhere, so you can plug in <em>x</em> = 0 to get 36•1/2 = 18.

8 0

3 years ago