Answer:
x = -36, y = 6, z = -6
Step-by-step explanation:
The requirement x/z = -z means x = -z².
The requirement x/y = z means x = yz.
These two requirements together mean yz = -z², or y = -z.
The requirements that z/2 and z/3 are integers mean that z is a multiple of 2·3 = 6. The smallest magnitude non-zero multiple is z=-6 (since we also require z < -z).
Using z=-6, we have x = -z² = -36; y = -(-6) = 6.
For some positive integer n, ...
... x = -36n², y = 6n, z = -6n.
(2 * (4-1) )^2
I'm assuming that's what the problem is.
(2 * 3) ^2
6^2
36
Answer:
Scores = 8
Step-by-step explanation:
To solve variation problems, you make mild assumptions and analogies
Let's score be represented with S
Let's Absences be represented with A.
Therefore
S varies inversely as A
S ~ 1/A
S = K/A
The K represents a contant notation so that we can easily figure the variation problem.
When Absences were 2
Scores were 12
S = K/A
12 = K / 2
Cross Multiply.
K = 24.
It means that, S = 24 / A.
For a student with 3 absences, the score would be:
S = 24 / A
S = 24 / 3
S = 8
Math is fun!
Answer:
B) Circle
Step-by-step explanation:
