(not a random sample, but chosen by first asking all 570 students the question and choosing 100 to reflect the proportion, and assuming they didn't change their answers and didn't lie)
then 41% of students have multiple pets so 0.41×570=234 have multiple pets.
45=1×5×9 so 45×1×1=45. 5×9×1=45. 9×5×1=45. 45×1×1=45 .and ,then 1×5×9=45 sooo if ABC are treated as identical variables number of solutions can be those 5 steps about to find all the number of positive integral solutions ...
