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Vladimir79 [104]
3 years ago
5

HELP! WILL GIVE BRANLIEST!

Mathematics
1 answer:
mars1129 [50]3 years ago
8 0

Answer:

D

Step-by-step explanation:

This is your answer because first you have 3x10-6 and 2x1030 what you have to do is that first you multiply 3 x 2 equals to 6 then, 10 x 1 = 10 then you have to multiply 30 x 6 = 180 then you put it together and your answer is 6x10-180

Hope this helps :)

pls mark me brainlist

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Answer:

Students should be able to find the x-intercepts of a quadratic function using both factoring and completing the square. All that should be given to students is the standard form of a quadratic equation in the form y = ax^2 + bx + c.

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Prove that an integer consisting of 3n ones is divisible by 3n (e.g. 111 is divisible by 3, 111,111,111 is divisible by 9, etc.)
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For proof of 3 divisibility, abc is a divisible by 3 if the sum of abc (a + b + c) is a multiple of 3.

<h3>Integers divisible by 3</h3>

The proof for divisibility of 3 implies that an integer is divisible by 3 if the sum of the digits is a multiple of 3.

<h3>Proof for the divisibility</h3>

111 = 1 + 1 + 1 = 3  (the sum is multiple of 3 = 3 x 1)  (111/3 = 37)

222 = 2 + 2 + 2 = 6 (the sum is multiple of 3 = 3 x 2)  (222/3 = 74)

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Thus, abc is a divisible by 3 if the sum of abc (a + b + c) is a multiple of 3.

Learn more about divisibility here: brainly.com/question/9462805

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2 years ago
The following table gives results from two groups of students who took a nonproctored test. Use a 0.01 significance level to tes
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Answer:

Original claim is \mu_{1} =\mu_{2}

Opposite claim is \mu_{1} \neq \mu_{2}

Null and alternative hypotheses:

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H_{1} : \mu_{1} \neq \mu_{2}

Significance level: 0.01

Test statistic:

We can use TI-84 calculator to find the test statistic and P-value. The steps are as follows:

Press STAT and the scroll right to TESTS

Scroll down to 2-SampTTest... and scroll to stats.

Enter below information.

\bar{x_{1}}=70.29

Sx1=22.09

n_{1} = 30

\bar{x_{2}}=74.26

Sx2=18.15

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\mu_{1} \neq \mu_{2}

Pooled: Yes

Calculate.

The output is in the attachment.

Therefore, the test statistic is:

t=-0.78

P-value: 0.4412

Reject or fail to reject: Fail to reject

Final Conclusion: Since the p-value is greater than the significance level, we, therefore, fail to reject the null hypothesis and conclude that the there is sufficient evidence to support the claim that the samples are from populations with the same mean.

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