Answer:
Step-by-step explanation:
(3,0),(4,1) ⇒ (x₁,y₁),(x₂,y₂)
to find the equation of the line
y-y₁= {(y₂-y₁)/(x₂-x₁)}(x-x₁)
y-0= [(1-0)/(4-3)] (x-3)
y-0 = 1/1(x-3)
y-0 = x-3
y= x-3+0
y=x-3
compare to y=mx+c, where m is the gradient and c is the intercept on y-axis
m=1, c=-3
∴the y-intercept of the line is -3
Answer:
I think it is c
Step-by-step explanation:
I might be wrong wait for a second answer if it is the same then I think I am right
Step 1: Find the area of the bases (triangles)
A = 1/2 * base * height
A = 1/2 * 16 * 6
A = 48
48 + 48 = 96
Area of the triangles = 96 cm^2
Step 2: Find the area of the sides (rectangles)
A = base * height
A1 = 16 * 12
A1 = 192
A2 = 10 * 12
A2 = 120
120 + 120 = 240
240 + 192 = 432 cm^2
Step 2: Add the areas together
96 + 432
528 cm^2
Hope this helps!! :)
Answer:
It is a rational number
Step-by-step explanation:
It is a rational number because -6/7 is equal to -0.857142 repeating. And a rational number repeats.
Hope this helps☝️☝☝
Answer:
![(x+8)^2 +(y-4)^2 = 25](https://tex.z-dn.net/?f=%20%28x%2B8%29%5E2%20%2B%28y-4%29%5E2%20%3D%2025)
Step-by-step explanation:
Assuming this complete problem: "A cell tower is located at (-8, 4) and transmits a circular signal that covers three major cities. The three cities are located on the circle and have the following coordinates: G (-4, 7), H (-13, 4), and I (-8, -1). Find the equation of the circle"
For this case the generla equation for the circle is given by:
![(x-h)^2 +(y-k)^2 = r^2](https://tex.z-dn.net/?f=%20%28x-h%29%5E2%20%2B%28y-k%29%5E2%20%3D%20r%5E2)
From the info we know that the tower is located at (-8, 4) so then h = -8 and k = 4, so then we need to find the radius. So we have the equation like this:![(x+8)^2 +(y-4)^2 = r^2](https://tex.z-dn.net/?f=%20%28x%2B8%29%5E2%20%2B%28y-4%29%5E2%20%3D%20r%5E2)
If the 3 points are on the circle then satisfy the equation. We can use the first point (-4,7) and if we replace we can find the value for ![r^2](https://tex.z-dn.net/?f=r%5E2)
![(-4+8)^2 +(7-4)^2 =25= r^2](https://tex.z-dn.net/?f=%20%28-4%2B8%29%5E2%20%2B%287-4%29%5E2%20%3D25%3D%20r%5E2)
So then ![r = \sqrt{25}=5](https://tex.z-dn.net/?f=%20r%20%3D%20%5Csqrt%7B25%7D%3D5)
And if we replace the second point we got this:
![(-13+8)^2 +(4-4)^2 = 25 =r^2](https://tex.z-dn.net/?f=%20%28-13%2B8%29%5E2%20%2B%284-4%29%5E2%20%3D%2025%20%3Dr%5E2)
And for the third point we have:
![(-8+8)^2 +(-1-4)^2 = 25 =r^2](https://tex.z-dn.net/?f=%20%28-8%2B8%29%5E2%20%2B%28-1-4%29%5E2%20%3D%2025%20%3Dr%5E2)
And we got the same result.
So then our final equation is given:
![(x+8)^2 +(y-4)^2 = 25](https://tex.z-dn.net/?f=%20%28x%2B8%29%5E2%20%2B%28y-4%29%5E2%20%3D%2025)