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Lostsunrise [7]
3 years ago
11

11. 4p2 + 7p + 3 factoring equations

Mathematics
2 answers:
Natalka [10]3 years ago
8 0

Answer:

\huge\boxed{4p^2+7p+3=(p+1)(4p+3)}

Step-by-step explanation:

4p^2+7p+3\\\\=4p^2+\underbrace{4p+3p}_{7p}+3\\\\=4p(p+1)+3(p+1)\\\\=(p+1)(4p+3)

Scrat [10]3 years ago
7 0

Answer:

Step-by-step explanation:

4p² + 7p + 3 = 4p² + 4p + 3p + 3

                    = 4p*(p + 1) + 3*(p + 1)

                    = (p + 1)(4p + 3)

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(4x^2-2x-4)(2x+4) what is<br> the product of the polynomials below?
tatiyna

Answer:

8x³ + 12x² - 16x - 16

General Formulas and Concepts:

  • Order of Operations: BPEMDAS
  • Distributive Property

Step-by-step explanation:

<u>Step 1: Define expression</u>

(4x² - 2x - 4)(2x + 4)

<u>Step 2: Simplify</u>

  1. Expand:                                       8x³ - 4x² - 8x + 16x² - 8x - 16
  2. Combine like terms (x²):             8x³ + 12x² - 8x - 8x - 16
  3. Combine like terms (x):              8x³ + 12x² - 16x - 16
7 0
3 years ago
Help Me With This Question
Anastaziya [24]
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7 0
3 years ago
I will upvote and give brainliest answer
zloy xaker [14]

Answer:

x=17

Step-by-step explanation

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6 0
3 years ago
Brian is solving the equation x squared minus three-fourths x = 5. What value must be added to both sides of the equation to mak
Allushta [10]

Answer:

  StartFraction 9 Over 64 EndFraction

Step-by-step explanation:

He must add the square of half the x coefficient. That coefficient is 3/4, so half of it is 3/8 and the square of that is ...

  (3/8)^2 = 9/64

Brian mus add 9/64 to boths sides of the equation.

6 0
3 years ago
Read 2 more answers
Convert into mixed number 81/3 and -29/2
LuckyWell [14K]
Hmmmm to convert from improper to mixed, simply do the division of both, the quotient gets upfront, the remainder as the numerator, for example,

how many times 3 goes into 81?  well, 27 times, with a remainder of 0, thus  \bf 27\frac{0}{3}

how many times does 2 go into 29?  well  14 times, with a remainder of 1, thus  \bf -14\frac{1}{2}
8 0
3 years ago
Read 2 more answers
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