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Norma-Jean [14]
3 years ago
15

HELPPPP What is the range of g

Mathematics
1 answer:
dimulka [17.4K]3 years ago
3 0

The range is how long the graph extends vertically. So, the lowest value is -9 (since the graph extends down until -9) and the highest value is 9 (since the graph extends up until 9). The lowest value goes in the first box and the highest value goes in the second box. The range is:

-9 ≤ <em>g</em>(<em>t </em>) ≤9


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vfiekz [6]

Answer:

Helppppppp Neeeeeeeeded asapppppp

Step-by-step explanation:

7 0
3 years ago
I'll give you brainliest! Just need help with 5-10! (Least common factors)
umka2103 [35]

Answer:

  • 60
  • 30
  • 48
  • 42
  • 45
  • 55

Step-by-step explanation:

5.

12,\:30\\\\\mathrm{Prime\:factorization\:of\:}12:\quad 2\times\:2\times\:3\\\mathrm{Prime\:factorization\:of\:}30:\quad 2\times\:3\times\:5\\\\=2\times\:2\times\:3\times\:5\\\\=60

6.

6,\:10\\\\\mathrm{Prime\:factorization\:of\:}6:\quad 2\times\:3\\\mathrm{Prime\:factorization\:of\:}10:\quad 2\times \:5\\\\=2\times \:3\times \:5\\\\=30

7.

16,\:24\\\\\mathrm{Prime\:factorization\:of\:}16:\quad 2\times \:2\times\:2\times\:2\\\mathrm{Prime\:factorization\:of\:}24:\quad 2\times\:2\times\:2\times\:3\\\\=2\times\:2\times\:2\times\:2\times\:3\\\\=48

8.

14,21\\\\\mathrm{Prime\:factorization\:of\:}14:\quad 2\times\:7\\\mathrm{Prime\:factorization\:of\:}21:\quad 3\times\:7\\\\=2\times\:7\times\:3\\\\=42

9.

9,15\\\\\mathrm{Prime\:factorization\:of\:}9:\quad 3\times\:3\\\mathrm{Prime\:factorization\:of\:}15:\quad 3\times\:5\\\\=3\times\:3\times\:5\\\\=45

10.

5,\:11\\\\\mathrm{Prime\:factorization\:of\:}5:\quad 5\\\mathrm{Prime\:factorization\:of\:}11:\quad 11\\\\=5\times \:11\\\\=55

5 0
3 years ago
Please help !!! Thanks :)
Tpy6a [65]
Pair 2 is a reflection. If you rotated it it would be flipped, so that doesn’t make sense.
7 0
3 years ago
Read 2 more answers
Brainliest for a math answer
erastovalidia [21]
Question 5- is 9
question 6- is 9
question 7-is 4
question 8-is 21
Question 9-is 2 
question 10-not sure sorry :(



Tell me if your right ;) 


5 0
3 years ago
Read 2 more answers
An objects speed can be modeled with the equation s=24(1.06)^t where s represents its speed in miles per hour and t represents t
4vir4ik [10]
s = 24(1.06)^{t} &#10;

24 is the numerical coefficient 

1.06 is the base of the power with exponent t
7 0
3 years ago
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