Answer:
A) a cycle has begun in which personal computer users
Explanation:
Option A as already used in the question fits and and completes the question correctly, this is because the because the writter is trying to communicate a new 'era', 'dispensention', 'period' or 'season'.... this is appropriately communicated with the word 'cycle'.
Answer:
int second_to_last = (number/10)%10;
int third_to_last = (number/100)%10;
Explanation:
The first expression int second_to_last = (number/10)%10; first divide the number by ten and then get modulus by dividing by ten again which will then give the second to last digit.
Assuming number is 146 the second to last digit will be 4.
for the second expression int third_to_last = (number/100)%10; first divide the number by hundred and then get modulus by dividing by ten which will then give the third to last digit.
Assuming number is 4368 the third to last digit will be 3.
Answer:
Yes those are the correct order.
Explanation:
Answer:
WWII; Manhattan Project.
Explanation:
Computer simulation refers to a mathematical model designed and developed to predict the outcome or behavior of a hypothetical or real-life scenario on a computer system, so as to illustrate and understand how the system functions.
Historically, computer simulations were first developed during World War II (WWII) as a part of the Manhattan Project.
For example, SimpleScalar refers to a computer architectural simulating software application or program which was designed and developed by Todd Austin at the University of Wisconsin, Madison, United States of America. It is an open source simulator written with "C" programming language and it's used typically for modelling virtual computer systems having a central processing unit (CPU), memory system parameters (hierarchy), and cache.
Answer:
Following are the answer to this question:
Explanation:
In option 1:
The value of n is= 7, which is (base case)

when n=k for the true condition:

when n=k+1 it tests the value:

since k>6 hence the value is KH>3 hence proved.
In option 2:
when:
for n=1:(base case)

0<=0 \\ condition is true
when the above statement holds value n=1
when n=k

when n=k+1


![[\therefore KH>K \Rightarrow \log(KH>\loK)]](https://tex.z-dn.net/?f=%5B%5Ctherefore%20KH%3EK%20%5CRightarrow%20%20%5Clog%28KH%3E%5CloK%29%5D)
In option 3:
when n=1:

when n=k
![\to (A_1\cap A_2 \cap.....A_k) \cup B\\=(A_1\cup B) \cap(A_2\cup B_2)....(A_k \capB).....(a)\\\to n= k+1\\ \to (A_1\cap A_2 \cap.....A_{kH}) \cup B= (A_1\cup B)\\\\\to [(A_1\cap A_2 \cap.....A_{k}) \cup B]\cap (A_{KH}\cup B)\\\\\to [(A_1\cup B) \cap (A_2 \cup B) \cap (A_3\cup B).....(A_k\cup B)\cap (A_{k+1} \cup B)\\\\ \ \ \ \ \ \ substituting \ equation \ a \\\\](https://tex.z-dn.net/?f=%5Cto%20%28A_1%5Ccap%20A_2%20%5Ccap.....A_k%29%20%5Ccup%20B%5C%5C%3D%28A_1%5Ccup%20B%29%20%5Ccap%28A_2%5Ccup%20B_2%29....%28A_k%20%5CcapB%29.....%28a%29%5C%5C%5Cto%20n%3D%20k%2B1%5C%5C%20%5Cto%20%28A_1%5Ccap%20A_2%20%5Ccap.....A_%7BkH%7D%29%20%5Ccup%20B%3D%20%28A_1%5Ccup%20B%29%5C%5C%5C%5C%5Cto%20%20%5B%28A_1%5Ccap%20A_2%20%5Ccap.....A_%7Bk%7D%29%20%5Ccup%20B%5D%5Ccap%20%28A_%7BKH%7D%5Ccup%20B%29%5C%5C%5C%5C%5Cto%20%20%5B%28A_1%5Ccup%20B%29%20%5Ccap%20%28A_2%20%5Ccup%20B%29%20%5Ccap%20%28A_3%5Ccup%20B%29.....%28A_k%5Ccup%20B%29%5Ccap%20%28A_%7Bk%2B1%7D%20%5Ccup%20B%29%5C%5C%5C%5C%20%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20substituting%20%5C%20equation%20%5C%20a%20%5C%5C%5C%5C)
hence n=k+1 is true.