Answer:
controls, code, protect, and add-ins!
Explanation:
edge 2021
Graphics software
Hope it helps
Answer:
"The value of the variable will remain the same which is already have when the sub-processor is called".
Explanation:
The above question said that:-
void fun(int a)
{
a=a+1;
}
void main()
{
int a=5;
fun(a);
}
//what will be the value of a in the main function after the fun function is excuted.
- Then the answer is: the value of a will be 5 in the main function.
- It is because when the fun function is called, then a variable that is defined in the fun function is a local variable for fun function. That scope after the fun function is null.
- The a variable inside the fun function is a different variable and the main function a variable is also a different variable.
- So when the user prints the value of a variable inside the fun function, it will give the result as 6.
- But when he prints the value of a variable inside the main function, then it will give the value as 5.
Answer:
Kasiski’s method for determining 't' works for Vigenère cipher as well. The only difference is therefore in the second stage of the attack. In the second stage, one needs to build a frequency table for each of the 't' keys, and carry out an attack like on the mono-alphabetic cipher. Given a long enough plaintext, this will work successfully.
Explanation:
Kasiski method is a method of attacking polyalphabetic substitution ciphers such as Vigenère cipher. It is also called Kasiski test or Kasiski examination.
The method involve finding the length of the keyword and then dividing the message into that many simple substitution cryptograms. Frequency analysis could then be used to solve the resulting simple substitution.
Answer:
ifstream inputFile;
inputFile.open("Friends.txt");
Explanation:
Though, the programming language is not stated, questions like this are often from C++.
The first statement defines the ifstream object using the following syntax.
ifstream [object_name]
In this case, the object name is inputFile
So, the syntax becomes
ifstream inputFile;
The next line opens a file using the following syntax.
[object_name].open("Filename")
Here, object_name is inputFile and filename is Friends.txt
So, the open statement becomes
inputFile.open("Friends.txt")
