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Blababa [14]
2 years ago
9

F(40)=0.015(40)+56.53

Mathematics
1 answer:
Tems11 [23]2 years ago
6 0

Answer:

F(40)=57.13

Step-by-step explanation:

0.015(40)=.6

.6+56.53=57.13

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Which expression is equivalent to (2x – 3)2 – 3.5x2(2x –5) + 6x(2.5x2 – x + 3.1)?
Olegator [25]

Answer:

Yuhh the answers c dawhggg trus me i just did the same thing lawl!

Step-by-step explanation:

5 0
3 years ago
Simplify 3x + 5 + 7 x - 3 - x + 2​
stira [4]

Before we do this problem, let's go over a little algebra terminology.

The number in front of your variable is called your <em>coefficient </em>and notice that the <em>x</em> at the end of the problem does not have a coefficient.

When that happens, when there is no number in front of your variable, you can put a 1 there to fill that position. So -x can be thought of as -1x.

Next let's change all our minus signs to plus negatives.

So the problem reads 3x + 5 + 7x + -3 + -1x + 2.

Now let's simplify this by combining like terms.

We can combine our "x" terms first.

3x + 7x + -1x simplifies to +9x.

Now, 5 + -3 + 2 simplifies to 4.

So our answer is 9x + 4.

8 0
2 years ago
Read 2 more answers
If you roll a 6-sided die 54 times, what is the best prediction possible for the number of times you will roll an odd number?
asambeis [7]

Answer:

9 times

Step-by-step explanation:

I took 54 and divided it by six and got nine

3 0
3 years ago
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if a pair of standard dice are rolled what is the probability that one die shows a six but not both of them. reduced fraction an
Novay_Z [31]

Answer:

P=\frac{5}{18}

Step-by-step explanation:

we know that

The probability of an event is the ratio of the size of the event space to the size of the sample space.  

The size of the sample space is the total number of possible outcomes  

The event space is the number of outcomes in the event you are interested in.  

so  

Let

x------> size of the event space

y-----> size of the sample space  

if a die is rolled the sample space is

\{1,2,3,4,5,6\}

if two dice rolled the sample space is

\{1,2,3,4,5,6\}*\{1,2,3,4,5,6\}

so

The possible pairs are

y=6*6=36

The size of the event space x is

\{(1,6),(2,6),(3,6),(4,6),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5)\}

x=10

P=\frac{x}{y}

substitute

P=\frac{10}{36}

Simplify

P=\frac{5}{18}

6 0
2 years ago
Solve for X.<br> Need to show the work. <br> Can someone help me?
Aleks [24]
I believe X equals -10.

7 0
2 years ago
Read 2 more answers
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