Answer:
Enlargement.
Scale Factor: 3
Step-by-step explanation:
Use points to find the enlargement. Typically, you will use all the points.
A(1 , 1) ⇒ A'(3 , 3)
B(2 , 1) ⇒ B'(6 , 3)
C(1 , 2) ⇒ C'(3 , 6)
D(2 , 2) ⇒ D'(6 , 6)
To find the scale factor, simply divide the Point' with the original Point. Use any number.
A'(3 , 3)/(A(1 , 1)) = 3
B'(6 , 3)/(B(2 , 1)) = 3
C'(3 , 6)/(C(1 , 2)) = 3
D'(6 , 6)/(D(2 , 2)) = 3
Your scale factor is 3.
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1.The measure of center that is most appropriate for this situation is the MEDIAN. This is because, one of the number given is an outlier, that is, it is much greater than the rest of the given numbers. If the mean of the number given is calculated, it will be discovered that the mean value obtained is higher than most of the scores in the data set, thus,the mean is not a suitable measure of central tendency in this case.
2. To find the median of the given numbers, arrange them in a descending order and add the two numbers in the middle then divide the value by 2.
That is, 0, 0, 1, 1, 2, 2, 2, 14.
The two numbers in the middle is 1 and 2.
Median = [1 + 2] / 2 = 3/2 = 1.5
Therefore, the median is 1.5
Answer:
7/3
Explanation:
The slope of the line is equal to the rise/run, or in other words, the number of units the line travels upwards over the number of units the line travels to the right.
We can identify the slope using any two points on the line. Here, we can use the two points that are marked on the picture. The second point is 7 units above the first and 3 units to the right of the first, so the slope of the line is equal to 7/3.
Another way to calculate the slope of the line is the use this formula:
(y2-y1)/(x2-x1)
The first point is at the coordinate (1,-4) and second point is at the coordinate (4,3). When we plug these two coordinates into the equation, we get this:
(y2-y1)/(x2-x1)
->(3-(-4))/(4-1)
When we simply the fraction, we would get 7/3 and that would give us the slope.
I hope this helps!
Answer:

Step-by-step explanation:
Substitute the value of the variable into the equation and simplify.