Question
Cable company A charges $45 a month for cable plus a $18 installation fee. Cable B charges $39 a month for cable plus a $30 fee for installation. Which inequality can be used to find out when the monthly cost for Cable company A is less than Cable company B?
a)39x+30<45x+18
b) 45x+18>39x+30
c) 45x+18<39x+30
d)39x+18<45x+30
Answer:
c) 45x+18<39x+30
Step-by-step explanation:
Step 1
We have to find the Algebraic expressions for the cable companies
Cable company A charges $45 a month for cable plus a $18 installation fee.
Let the number of months be represented as x
Hence, this is represented as:
$45 × x + $18
= 45x + 18
Cable B charges $39 a month for cable plus a $30 fee for installation.
Let the number of months be represented as x
Hence, this is represented as:
$39 × x + $30
= 39x + 30
The inequality that can be used to find out when the monthly cost for Cable company A is less than Cable company B?
= Cable company A < Cable company B
= 45x + 18 < 39x + 30
Therefore option c is correct
<span>A. 504 in2 B. 396 in2 C. 312 ... ... A. 155 in2 B. 270 in2 C. 300 in2 D. 310 in2 H=15 l=5 w=4 ... The formula for the rectangular prism surface area is 2(wl+hl+hw).</span><span>300 in2</span>
It’s d because one week would b 210 making it 790 and 3 more days would make it 700. 7+3 = 10 days
Answer:
1st one, A
Step-by-step explanation:
Just subsititute the given values in the formula
x = 4 * 5 ( 7 + 9 ) = 320
