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Svet_ta [14]
3 years ago
5

I need Help with my multi step equations!

Mathematics
1 answer:
finlep [7]3 years ago
3 0
15. -6b+2-5b=36+6b
-11b+2=36+6b
-17b+2=36
-17b=34
b=-2

16. 48+32h=-39+3h
48+29h=-39
29h=-87
h=-3


17. -20r+5=-20r+20
5¥20
no solution

18. a+7=7a+21+18-6a
a+7=a+39
7¥39
no solution

19. -8b+24=24-24b
16b+24=24
16b=0
b=0

20. 5a+4=5a-10
4¥-10
no solution
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Simplify the expression. 8x^-10 y^'6 -2x^2y^-8 Write your answer without negative exponents.​
sergij07 [2.7K]

Answer:

8x^{-10}y^6 - 2x^2y^{-8} = \frac{8y^{14} - 2x^{12}}{x^{10}y^8}

Step-by-step explanation:

Given

8x^{-10}y^6 - 2x^2y^{-8}

Required

Simplify

Rewrite as:

8x^{-10}y^6 - 2x^2y^{-8} = \frac{8y^6}{x^{10}} - \frac{2x^2}{y^8}

Take LCM

8x^{-10}y^6 - 2x^2y^{-8} = \frac{8y^6*y^8 - 2x^2 * x^{10}}{x^{10}y^8}

Apply law of indices

8x^{-10}y^6 - 2x^2y^{-8} = \frac{8y^{14} - 2x^{12}}{x^{10}y^8}

8 0
3 years ago
Find two integers whose sum is -20 and product is 99
Brums [2.3K]

Answer:

Step-by-step explanation:

let the integers be x and y

x+y=-20

y=-20-x

xy=99

x(-20-x)=99

-20x-x²=99

x²+20x+99=0

x²+11x+9x+99=0

x(x+11)+9(x+11)=0

(x+11)(x+9)=0

x=-11,-9

when x=-11

-11+y=-20

y=-20=11=-9

when x=-9

-9+y=-20

y=-20+9=-11

so integers  are -11,-9

8 0
3 years ago
Read 2 more answers
Solve. Check your solution.<br> -4+s= -68
Andrews [41]
-64 + -4 = -68

That is because 64 + 4 = 68 and the negatives in this case are the same way as if it was all positive.
6 0
3 years ago
Read 2 more answers
Sherri saves nickels and dimes in a coin purse for her daughter. The total value of the coins in the purse is $0.95. The number
forsale [732]
I’m guessing that this is for systems of equations?
n - nickels
d - dimes

These are the equations you start off with.
n = 5d-2
0.95 = 0.10d+0.05n

Substitute the top equation for n into the variable n in the bottom equation.
0.95 = 0.10d+0.05(5d-2)

Solve for d.
0.95 = 0.10d+0.25d-0.10
1.05 = 0.35d
3 = d

Substitute d into the top equation and solve for n.
n = 5(3)-2
n = 15-3
n = 12

There are 3 dimes and 12 nickels in the coin purse! Hope this helped <3

7 0
3 years ago
Read 2 more answers
Given the two vertices and the centroids of a triangle, how many possible locations are there for the third vertex?
hoa [83]

Answer:

  1

Step-by-step explanation:

The centroid is the average of the coordinates of the three vertices. If you know two vertices (A and B) and the centroid (Q), then the third vertex (C) is ...

  C = 3Q -A -B

It has only one possible location.

7 0
3 years ago
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