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alex41 [277]
3 years ago
10

-7/3 __ -5/2 (=, <,>, )​

Mathematics
1 answer:
Natalka [10]3 years ago
5 0
-7/3 is less than -5/2, so the closed end should be be -7/3 and the open end should be by -5/2

-7/3 simplifies to -2 and 1/3
-5/2 simplifies to -2 and 1/2

And 1/2 is greater than 1/3
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Each item produced by a certain manufacturer is independently of acceptable quality with probability 0.95. Approximate the proba
Diano4ka-milaya [45]

Answer:

The probability that at most 10 of the next 150 items produced are unacceptable is 0.8315.

Step-by-step explanation:

Let <em>X</em> = number of items with unacceptable quality.

The probability of an item being unacceptable is, P (X) = <em>p</em> = 0.05.

The sample of items selected is of size, <em>n</em> = 150.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 150 and <em>p</em> = 0.05.

According to the Central limit theorem, if a sample of large size (<em>n</em> > 30) is selected from an unknown population then the sampling distribution of sample mean can be approximated by the Normal distribution.

The mean of this sampling distribution is: \mu_{\hat p}= p=0.05

The standard deviation of this sampling distribution is: \sigma_{\hat p}=\sqrt{\frac{ p(1-p)}{n}}=\sqrt{\frac{0.05(1-.0.05)}{150} }=0.0178

If 10 of the 150 items produced are unacceptable then the probability of this event is:

\hat p=\frac{10}{150}=0.067

Compute the value of P(\hat p\leq 0.067) as follows:

P(\hat p\leq 0.067)=P(\frac{\hat p-\mu_{p}}{\sigma_{p}} \leq\frac{0.067-0.05}{0.0178})=P(Z\leq 0.96)=0.8315

*Use a <em>z</em>-table for the probability.

Thus, the probability that at most 10 of the next 150 items produced are unacceptable is 0.8315.

5 0
3 years ago
I want help its urgent!!! <br><br>(iv), (v), (vi) Questions​
Artist 52 [7]

Solution:

iv) Given equation: x^{2} - y^{2} - 4x - 2y + 3

Since we are given two variables, we need to split the original expression into two quadratic expressions as

x^{2} - 4x + 4 - y^{2} - 2y - 1

Factoring x first:

x^{2} - 4x + 4 = x^{2} - 2x - 2x + 4

= x (x - 2) - 2 (x-2)

= (x-2)(x-2)

= (x-2)^{2}

Factoring y now:

-y^{2} - 2y - 1 = -1(y^{2} + 2y + 1)

= -1(y^{2} + y + y + 1)

= -1[ y(y+1) + 1(y+1)]

= -1 [(y+1)(y+1)]

= (y+1)(-y-1)

Therefore, the original expression becomes

(x-2)^{2}+(y+1)(-y-1)\\or \\(x-2)(x-2) + (y+1)(-y-1)

7 0
3 years ago
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Answer:

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Step-by-step explanation:

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Hence option a I believe is true
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