Answer:
i would go for the first one but im not entirely sure
i suggest you wait to see other people's answers
Slope, found using the points is -55/11 = -5
We use that for the equation y=mx+b where m=-5. Since we also know one of the points, we can plug that in and find b
-12=-5(4)+b
-12=-20+b
8=b
So the equation of the line is y=-5x+8
Answer:
6(a)+14
Step-by-step explanation:
First you need to find f(a) and f(2) separately, then add them together after
f(a) = 6(a)+1
f(2) = 6(2)+1 = 12+1 = 13
so f(a)+f(2) = 6(a)+1+13 = 6(a)+14
<span>For a parallelogram to be proven to be a rectange, the opposide sides must be parallel and the two adjacent sides must be perpendicular.
For two parallel sides, the slope of the two sides is equal.
Thus, for the parallelogram to be a rectangle, AB is parallel to CD.
The slope of AB = (y2 - y1)/(x2 - x1) while the slope of CD = (y4 - y3)/(x4 - x3)
Also, BC is perpedicular to CD.
For two perpendicular sides, the product of the slopes is -1.
The slope of BC is given by (y3 - y2)/(x3 - x2).
Therefore, for the parallelogram to be a rectangle.
(y2 - y1)/(x2 - x1) = (y4 - y3)/(x4 - x3) and (y4 - y3)/(x4 - x3) x (y3 - y2)/(x3 - x2) = -1.
The third option is the correct answer.</span>
Answer:
ok so its the first one
Step-by-step explanation:
it shows th same kind of aleration
