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anzhelika [568]
2 years ago
7

Please please help! first answer gets brainliest

Mathematics
1 answer:
Citrus2011 [14]2 years ago
7 0

Answer:

u cant give brainliest to someone when only one person has answered

Step-by-step explanation:

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-43/100 as a decimal
lutik1710 [3]

Answer:

-0.43

Step-by-step explanation:

100/-43

6 0
3 years ago
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The price of milk increased from $3.25 to $3.75. What is the percent of change for the price of milk to the nearest tenth? Show
nikitadnepr [17]
Percent = part/whole

It wants you to find the % of change so it's 3.25 / 3.75
And that comes out to be 0.86 (with the 6 repeating)
So you move the decimal over 2 places to find the percent.
And then it's 1 - Ans

The answer is 13.33%
3 0
3 years ago
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The volume of a cone is 1/3 that of a cylinder when the radius and height are the same (v= 1/3(pi)(r)^2(h). What is the volume o
Ira Lisetskai [31]

\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}

Actually Welcome to the Concept of the Surface Areas and Volumes.

Since, Volume of cone = 1/3 π r^2 h,

here, r = 10 Inches and h= 12 inches, also π =3.14

so, VOC = 1/3 π (10)^2 × (20)

VOC = 1/3(3.14)(100)(20)= 2093.33 inch^3

=> so the volume of the cone is 2093.33 cubic inches.

5 0
3 years ago
A car insurance company has determined that 9% of all drivers were involved in a car accident last year. among 14 drivers living
andriy [413]

The probability of getting 3 or more who were involved in a car accident last year is 0.126.

Given 9% of the drivers were involved in a car accident last year.

We have to find the probability of getting 3 or more who were involved in a car accident last year if 14 were selected randomly.

We have to use binomial theorem which is as under:

nC_{r}p^{r} (1-p)^{n-r}

where p is the probability an r is the number of trials.

Probability that 3 or more involved in a car accident last year if 14 are randomly selected=1-[P(X=0)+P(X=1)+P(X=2)]

=1-{14C_{0}0.9^{0} (0.1)^{14} +14C_{1} (0.9)^{1} (0.1)^{13} +14C_{2} (0.9)^{2} (0.1)^{12}}

=1-{1*0.2670+14!/13!*0.9*0.29+14!/2!12!*0.0081*0.2358}

=1-{0.2670+0.3654+0.2358}

=1-0.8682

=0.1318

Among the options given the nearest is 0.126.

Hence the probability that 3 or more are involved in the accident is 0.126.

Learn more about probability at brainly.com/question/24756209

#SPJ4

7 0
1 year ago
HELP!! PLEASE, 3x/2 +2x/2=1+3x/2​
Natasha2012 [34]

Answer: x=1

Step-by-step explanation:

7 0
3 years ago
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