Given that g(x)=10x^2-100x+213 in vertex form is:
g(x)=10(x-5)2-37
The vertex form of an equation is given by the formula:
f(x)=a(x-h)^2+k
where the vertex is:
(h,k)
Therefore fro our expression the vertex of g(x) is (5,-37)
Please consider the complete question.
The base of a solid oblique pyramid is an equilateral triangle with a base edge length of 18 inches. What is the height of the triangular base of the pyramid?
First of all, we will draw an equilateral triangle.
Since the given triangle is equilateral triangle, so all sides will have same length that is 18 inches.
We know that height of an equilateral triangle is 
, where a is side length of equilateral triangle.
Therefore, the height of the given equilateral triangular base will be 
inches and option B is the correct choice.
area = l x w
area = 9 x 9
area = 81
Hope this was helpful. :-)
Answer:
66018.5 sq feet
Step-by-step explanation:
Area = πr²
To find the Radius R we need Diameter which 290 fee so:
R = Diameter / 2
R = 290/2
R = 145 ft
Now put values in Area Formula
Area = 3.14 x (145)^2
A = 66018.5 sq feet
This is an example of a quadratic equation.
Whenever you see that the variable x is raised to the second power, you have a quadratic equation. The graph of this will look like the letter U and be called a parabola.
