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mylen [45]
3 years ago
6

Solve for x (X-9)(x+5)=8(21)

Mathematics
1 answer:
emmasim [6.3K]3 years ago
7 0
I think the answer should be x = 10.101326
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Paladinen [302]

Answer:

5)216

6)18

7)5

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Step-by-step explanation:

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Drag each tile to the correct location on the table.
RoseWind [281]

Short-term investments characteristics  are:

  • More affected by rapid market changes.
  • Taxed at a higher rate.
  • Subject to more transaction fees.
  • Incurs more annual brokerage fees.

<h3>What are Long-Term Investments?</h3>

Others are:

Long-term investments characteristics  are:

  • Carries the risk of higher inflation.

Long-term investments are known to be a kind of assets that people or a firm intends to keep for a long period of time that is usually more than three years.

Note that Long-term investors usually take on a high degree of risk when one is said to be after higher returns.

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4 0
2 years ago
Answer fast but correctly​
olasank [31]

{m}^{2}  - n \\ Given, \:  \: m = 3 \:  \: n = 2, then, \\ \:  \:  {(3)}^{2}  - 2 \\  = 9 - 2 \\  = 7

<u>Answer</u><u>:</u>

<u>a.</u><u> </u><u>7</u>

Hope you could understand.

If you have any query, feel free to ask.

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2 years ago
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Help me with this pls​
Akimi4 [234]

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is that math????????????????

3 0
3 years ago
A piece of cardboard is 15 inches by 30 inches. A square is to be cut from each corner and the sides folded up to make an open-t
solmaris [256]

Answer:

Maximum volume = 649.519 cubic inches

Step-by-step explanation:

A rectangular piece of cardboard of side 15 inches by 30 inches is cut in such that a square is cut from each corner. Let x be the side of this square cut. When it was folded to make the box the height of box becomes x, length becomes (30-2x) and the width becomes (15-2x).

Volume is given by  

V = V = Length\times Width\times Height\\V = (30 - 2x)(15-2x)x= 4x^3-90x^2+450x\\So,\\V(x) = 4x^3-90x^2+450x

First, we differentiate V(x) with respect to x, to get,

\frac{d(V(x))}{dx} = \frac{d(4x^3-12x^2+9x)}{dx} = 12x^2 - 180x +450

Equating the first derivative to zero, we get,

\frac{d(V(x))}{dx} = 0\\\\12x^2 - 180x +450 = 0

Solving, with the help of quadratic formula, we get,

x = \displaystyle\frac{5(3+\sqrt{3})}{2}, \frac{5(3-\sqrt{3})}{2},

Again differentiation V(x), with respect to x, we get,

\frac{d^2(V(x))}{dx^2} = 24x - 180

At x =

\displaystyle\frac{5(3-\sqrt{3})}{2},

\frac{d^2(V(x))}{dx^2} < 0

Thus, by double derivative test, the maxima occurs at

x = \displaystyle\frac{5(3-\sqrt{3})}{2} for V(x).

Thus, largest volume the box can have occurs when x = \displaystyle\frac{5(3-\sqrt{3})}{2}}.

Maximum volume =

V(\displaystyle\frac{5(3-\sqrt{3})}{2}) = (30 - 2x)(15-2x)x = 649.5191\text{ cubic inches}

8 0
3 years ago
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