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Alina [70]
3 years ago
11

What is the intersection of AB and ED

Mathematics
1 answer:
Elan Coil [88]3 years ago
5 0

Answer:

point c is the intersection of line AB and ED

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5, 10, 12, 4, 6, 11, 13,5<br> calculate the mode
Radda [10]

Answer:

5

Step-by-step explanation:

Mode is which number occurs most, and in this set of data, 5 occurs two times.

7 0
3 years ago
HELP PLEASE ASAP IM ON THE LAST ONE
inna [77]

Answer:

y=9; z=16

Step-by-step explanation:

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Translate “the sum of 5 and x times 8” into mathematical symbols
Advocard [28]

Answer:

(5+x)8

Step-by-step explanation:

8 0
3 years ago
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Algebraic expression for 5 minus the product of y and 3
viva [34]

Answer:

5 - 3y

Step-by-step explanation:

Step 1: Convert product of y and 3 into numbers

Product = multiply

y = y

3 = 3

3y

Step 2: Convert 5 minus into numbers

minus = subtract

5 - 3y

4 0
3 years ago
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If a = (3-2√2) find the value of a4+ 1/a4 ​
FinnZ [79.3K]

Answer:

  1154

Step-by-step explanation:

Perhaps the easiest way to evaluate this numerical expression is to let a calculator do it. Alternatively, we can compute the value from a +1/a.

__

<h3>expression</h3>

Consider the square of a +1/a:

  (a +1/a)^2 = a^2 +2(a)(1/a) +1/a^2 = (a^2 +1/a^2) +2

This means ...

  a^2 +1/a^2 = (a +1/a)^2 -2

Similarly, using a^2 for 'a' in the above, we have ...

  a^4 +1/a^4 = (a^2 +1/a^2)^2 -2

<h3>numerical value</h3>

The value of a +1/a is ...

  a+\dfrac{1}{a}=3-2\sqrt{2}+\dfrac{1}{3-2\sqrt{2}}=(3-2\sqrt{2})+\dfrac{3+2\sqrt{2}}{3^2-(2\sqrt{2})^2}\\\\=(3-2\sqrt{2})+(3+2\sqrt{2})\\\\a+\dfrac{1}{a}=6

Then the value of a^2 +1/a^2 is 6^2 -2 = 34

and the value of a^4 +1/a^4 is 34^2 -2 = 1154

4 0
2 years ago
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