1.) p^2+14p-38=0 what the vertex?
1 answer:
Answer:
vertex = (- 7, - 87)
Step-by-step explanation:
given a parabola in standard form : ax² + bx + c : a ≠ 0
Then the x- coordinate of the vertex is
= -
p² + 14p - 38 is in standard form
with a = 1, b = 14, c = - 38, hence
= -
= -7
substitute x = - 7 into the equation for corresponding value of y
y = (- 7)² + 14(- 7) - 38 = 49 - 98 - 38 - - 87
vertex = (- 7, - 87)
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