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artcher [175]
3 years ago
11

1.) p^2+14p-38=0 what the vertex?

Mathematics
1 answer:
Lelu [443]3 years ago
3 0

Answer:

vertex = (- 7, - 87)

Step-by-step explanation:

given a parabola in standard form : ax² + bx + c : a ≠ 0

Then the x- coordinate of the vertex is

x_{vertex} = - \frac{b}{2a}

p² + 14p - 38 is in standard form

with a = 1, b = 14, c = - 38, hence

x_{vertex } = - \frac{14}{2} = -7

substitute x = - 7 into the equation for corresponding value of y

y = (- 7)² + 14(- 7) - 38 = 49 - 98 - 38 - - 87

vertex = (- 7, - 87)


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