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3 years ago

1.) p^2+14p-38=0 what the vertex?

Mathematics

1 answer:

Lelu [443]3 years ago

3 0

Answer:

vertex = (- 7, - 87)

Step-by-step explanation:

given a parabola in standard form : ax² + bx + c : a ≠ 0

Then the x- coordinate of the vertex is

$x_{vertex}$ = - $\frac{b}{2a}$

p² + 14p - 38 is in standard form

with a = 1, b = 14, c = - 38, hence

$x_{vertex }$ = - $\frac{14}{2}$ = -7

substitute x = - 7 into the equation for corresponding value of y

y = (- 7)² + 14(- 7) - 38 = 49 - 98 - 38 - - 87

vertex = (- 7, - 87)

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