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liraira [26]
3 years ago
7

What decimal is 1/10 of 0.08

Mathematics
1 answer:
Vera_Pavlovna [14]3 years ago
4 0
The answer is 0.008. Hopefully you understand why :)


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3x + 2.3 = 11.6 help please
Zielflug [23.3K]

<u><em>Solution:</em></u>

<u><em></em></u>x=3.1

Hope this helps!

6 0
1 year ago
Read 2 more answers
Which of the following do indexes and scales have in common?
statuscvo [17]

Answer:

c.They rank-order the units of analysis in terms of specific variables

Step-by-step explanation:

An index is a way  of compiling one score from a variety of  questions or statement that represents a belief, feeling or attitude.

Scales on the other hand measure levels of intensity at a variable level like how much a person agrees or disagrees with a particular statement.

The one thing common to both  indexes and scales is that

They rank-order the units of analysis in terms of specific variables.

4 0
3 years ago
Which is 9.5 expressed as a fraction in simplist form​
stealth61 [152]

Answer:

9 1/2

Step-by-step explanation:

9 and a half

6 0
3 years ago
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Anyone know this geometry question? Will give brainiest
Dafna11 [192]
The opposite angles equal each other, so X and Z are equal
 using that we solve for x by setting them equal:

6x-60 = 2x+68

subtract 2x from each side:

4x -60 = 68

add 60 to each side:

4x = 128
 divide both sides by 4
x = 128/4
x = 32

now we know x so we can solve everything else by replacing x with 32

WY = 3x+5 = 3(32)+5 = 96+5 = 101

angle Z = 2x+68 = 2(32)+68 = 64+132

the answer is C


5 0
2 years ago
Which statement accurately describes how to reflect point A(3,-1) over the y-axis?
Lyrx [107]

Answer:

The answer in the procedure

Step-by-step explanation:

we know that

The rule of the reflection of a point over the y-axis is equal to

A(x,y) ----->A'(-x,y)

That means -----> The x-coordinate of the image is equal to the x-coordinate of the pre-image multiplied by -1 and the y-coordinate of both points (pre-image and image) is the same

so

A(3,-1) ------> A'(-3,-1)

The distance from A to the y-axis is equal to the distance from A' to the y-axis (is equidistant)

therefore

To reflect a point over the y-axis

Construct a line from A perpendicular to the y-axis, determine the distance from A to the y-axis along this perpendicular line, find a new point on the other side of the y-axis that is equidistant from the y-axis

6 0
2 years ago
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