Graph this function: y+6=1/2(x-1)
2 answers:
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9514 1404 393
Answer:
2x -3y = 21
Step-by-step explanation:
The perpendicular line will have an equation with the x- and y-coefficients swapped and one of them negated. The constant will be the value that makes the equation true at the given point.
3x +2y = 6 . . . . . given equation
2x -3y = c . . . . . . coefficients swapped, one negated
2(6) -3(-3) = c = 21 . . . . . the value of c for the given point
The desired equation is ...
2x -3y = 21
Answer:
1) P(x) =14400x+10300 2)y=-4x+19 3) 4) x=-11
(Please check the pictures for better understanding)
Step-by-step explanation:
1) Firstly, let's organize the data. Let the dependent variable x be the years, and the Range P(x) the Profit. So arranging these linear functions y=ax+b and plugging the coordinates for each point (1, 24700) and (4, 67900). Goes:
24,700=x+b
67,900=4x +b
1.1)Solving for b, this Linear System of Equation by the Addition Method goes:
1.2) Now, let's find the slope based on those two points (1, 24700) and (4, 67900) and using the formula to find the slope:
So now we can write this Linear Equation for the Profit:
P(x) =14400x+10300
2) An equation of the line perpendicular to 4y=x-8 has a slope equal to =-
the line. In this case, an equation perpendicular to 4y=x-8 .
Rearranging the given equation of the line 4y=x-8 goes:
2.1) The slope of this new line is equivalent to m=-4 since -4 is opposite inverse value for the slope of its perpendicular line (1/4).
If the line passes through the point (6,-5), then this point already belongs to this line.
Then, we can write.
-5=-4(6)+b
-5=-24+b
-5+24=-24+24+b
b=19
Now we can write the function:
y=-4x+19
3) Firstly, let's rearrange the equation. Into a General Equation of the Line y=ax+b
2x+3y=5
-2x+2x+3y=5-2x
3y=5-2x
3.2) Let's find out b, the linear coefficient by plugging the coordinates of the point (-3,-8).
Also, Parallel lines have the same value for the slope such as
-8=-3(-2/3)+b
-8=2+b
-8-2=2-2+b
b=-10
Then the equation of this parallel line is:
4) Now on this last question, we have to find an equation of the line through the point (-11,-4) perpendicular to another line y=15
Suppose the slope of the first line is and the value of the slope of its perpendicular is
y=15 is a horizontal line with slope equals zero, we can rewrite it as y=0x+15.
Then the slope is zero for horizontal lines.
A perpendicular line to a horizontal line is a vertical one.
In addition to this, a vertical line passes through only one point in the x-axis. Then, there is no horizontal variation. This leads the formula of a slope to an undefinition for Real Set.
The only perpendicular line which passes through the point (-11,-4) to y=15 is the line x=-11.
