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3 years ago

The difference between three times a number and four more than two times the number

Mathematics

1 answer:

Diano4ka-milaya [45]3 years ago

4 0

Answer:

SOLUTION: The difference between three times a number and nine more than two times the number. 3x - (2x+9).

Step-by-step explanation:

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If A = [ 8 ] and B = 5 * 3), find 3A + B.

Diano4ka-milaya [45]

Answer: 3A =38+15=43

Step-by-step explanation:

8 0

2 years ago

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A card is drawn randomly from a standard 52-card deck. Find the probability of the given event. (a) The card drawn is 5. The pro

Dmitrij [34]

Answer:

a. 1 / 13
b. 3 / 13
c. 10 / 13

Step-by-step explanation:

There are four 5's in the deck. This means that, from 52 possible cards to drawn, we have 4 chances of drawing a 5. This means that the probability will be:

$p = \frac{4}{52}$

$p = \frac{1}{13}$

For every suit, there are three face cards, J, Q and K. There are 4 suits, so, the total number of face cards its:

$4 * 3 = 12$

The total possible cards are, still, 52, so, the probability will be

$p = \frac{12}{52}$

$p = \frac{3}{13}$

We know that the card drawn must be a face card, o not being a face card. There is no third choice here. So, the probability of drawing a face card OR not drawing a face car its:

$p = \frac{52}{52} = 1$

$p(the \ card \ is \ a \ face \ card) + p(the \ card \ is \ not \ a \ face \ card) = 1$

$p(the \ card \ is \ not \ a \ face \ card) = 1 - p(the \ card \ is \ a \ face \ card)$

but, we know that

$p(the \ card \ is \ a \ face \ card = \frac{3}{13}$

$p(the \ card \ is \ not \ a \ face \ card) = 1 - \frac{3}{13}$

$p(the \ card \ is \ not \ a \ face \ card) = \frac{10}{13}$

7 0

2 years ago

Given a triangle with b = 7, C = 3, and A = 37° what is the length of a? Round to the nearest tenth.

marissa [1.9K]

Answer: 4.9

Step-by-step explanation:

5 0

3 years ago

Round 111.11111 to the nearest ten thousandth. 111.11 111.111 111.1111 111.11111

Pachacha [2.7K]

Answer: C) 111.1111

<u>Step-by-step explanation:</u>

here are the place values to the right of the decimal.

decimal → tenths → hundredths → thousandths → ten thousandths

. 1 2 3 4

Round the number to 4 digits to the right of the decimal point.

4 0

3 years ago

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Given the function h(x) = —~2 – 6x + 17, determine the average rate of change

mamaluj [8]

Answer:

Average Rate of change of given function $h(x)=-x^2-6x+17$ is 2

Step-by-step explanation:

We are given function: $h(x)=-x^2-6x+17$ (considering x is missed)

We need to find average rate of change of the function over the interval $- 6 < x < -2$ .

$x_{1} = -6\\x_2 =-2$

Formula used to find average rate of change is: $Average \ Rate \ of \ Change =\frac{h(x_2)-h(x_1)}{x_2-x1}$

Finding f(x₁) and f(x₂)

$We \ have \ x_1=-6\\h(x_1)= -x^2-6x+17\\h(x_1)=-(-6)^2-6(-6)+17\\h(x_1)=-36+36+17\\h(x_1)=17$

$We \ have \ x_2=-2\\h(x_2)=-x^2-6x+17\\h(x_2)=-(-2)^2-6(-2)+17\\h(x_2)=-4+12+17\\h(x_2)=25$

Putting values in the formula of average rate of change

$Average \ Rate \ of \ Change =\frac{h(x_2)-h(x_1)}{x_2-x1}\\h(x_2)=25, h(x_1)=17, x_1 =-6 \ and \ x_2=-2\\Average \ Rate \ of \ Change =\frac{25-17}{-2-(-6)}\\Average \ Rate \ of \ Change =\frac{8}{4}\\Average \ Rate \ of \ Change =2$

So, Average Rate of change of given function $h(x)=-x^2-6x+17$ is 2

5 0

3 years ago