Answer:-126f-108
Step-by-step explanation:
9(-9f - 2)-9(5f +10)
-81f - 18 -9(5f + 10)
- 81f - 18 - 45f -90
- 126f - 18 - 90
-126f -108
which give you the answer -126f - 108
Answer:
answer is attached on the photo
Answer:
2nd option on the top right
Step-by-step explanation:
X²+15x+36<0
at first solve quadratic equation
D=b²-4ac= 225-4*1*36= 81
x=(-b+/-√D)/2a
x=(-15+/-√81)/2= (-15+/-9)/2
x1=(-15-9)/2=-12
x2=(-15+9)/2=-3
we can write x²+15x+36<0 as (x+12)(x+3)<0
(x+12)(x+3)<0 can be 2 cases, because for product to be negative one factor should be negative , and second factor should be positive
1 case) x+12<0, and x+3>0,
x<-12, and x>-3
(-∞, -12) and(-3,∞) gives empty set
or second case) x+12>0 and x+3<0
x>-12 and x<-3
(-12,∞) and (-∞,-3) they are crossing , so (-12, -3) is a solution of this inequality
Answer: 3
Step-by-step explanation:
5−(4−2−(6−6))
=3
