3 years ago

Write a quadratic function in vertex form whose graph has the vertex (1,8) and passes through the point (3,12)

Mathematics

1 answer:

just olya [345]3 years ago

5 0

Vertex form: y=(x-1)^2+8

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A triangle has vertices (-1, 2), (3, 1), and (7, 2). What is the approximate perimeter of the triangle? Round your answer to the

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Use the distance formula to find the length of the sides, then add them up to find the perimeter.

$\sf d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

For points in the form of (x1, y1), (x2, y2).

(-1, 2), (3, 1)

$\sf d=\sqrt{(3+1)^2+(1-2)^2}$

$\sf d=\sqrt{(4)^2+(-1)^2}$

$\sf d=\sqrt{16+1}$

$\sf d=\sqrt{17}$

(3, 1), (7, 2)

$\sf d=\sqrt{(7-3)^2+(2-1)^2}$

$\sf d=\sqrt{(4)^2+(1)^2}$

$\sf d=\sqrt{16+1}$

$\sf d=\sqrt{17}$

(7, 2), (-1, 2)

$\sf d=\sqrt{(-1-7)^2+(2-2)^2}$

$\sf d=\sqrt{(-8)^2+(0)^2}$

$\sf d=\sqrt{64+0}$

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So the perimeter will be:

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Write a quadratic function in vertex form whose graph has the vertex (1,8) and passes through the point (3,12)​

Write a quadratic function in vertex form whose graph has the vertex (1,8) and passes through the point (3,12)