$\bf \begin{cases}
x=\sqrt{3}\implies &x-\sqrt{3}=0\\
x=-4\implies &x+4=0\\
x=4\implies &x-4=0
\end{cases}
\\\\\\
(x-\sqrt{3})(x+4)(x-4)=\stackrel{y}{0}\implies (x-\sqrt{3})(\stackrel{\stackrel{difference}{of~squares}}{x^2-4^2})=y
\\\\\\
(x-\sqrt{3})(x^2-16)=y\implies x^3-16x-x^2\sqrt{3}+16\sqrt{3}=y
\\\\\\
x^3-x^2\sqrt{3}-16x+16\sqrt{3}=y$

7 0

3 years ago

Which of the following is the most appropriate unit to describe the rate at which water flows over Niagara Falls?

melomori [17]

C) Billion gallons per day, because the independent quantity is time in days and dependent quantity is volume of water in billion gallons.

Hope this helps!!

8 0

3 years ago

Read 2 more answers

one winter day the temperature ranged from a high of 20 f to a low of -25 f. by how many degrees did the temperature change?

Mamont248 [21]

Answer:

45 degrees

Step-by-step explanation:

you would do 20-(-25) then that turns to 20+25 and you get 45

6 0

3 years ago