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2 years ago

I need to figure out on how to do this, please help me

Mathematics

1 answer:

yanalaym [24]2 years ago

7 0

Answer:

Q = 108°

R = 72°

Step-by-step explanation:

Quadrilateral means this is a four-sided shape. Parallelogram means that both sets of opposite side are parallel, so all the angles are either equal or add up to 180° (supplementary)

The order of the letters matters bc PQRS means that you go along an edge from P to Q, but you have to go thru the middle of the shape to get from P to R. So P and Q add up to 180°.

P + Q = 180°

72° + Q = 180°

Q = 108°

Opposite from each other, across the middle of the shape, P and R are equal.

P = R = 72°

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1 year ago

The measure ∠BQS of is 80°. What is the m∠NQS? 42° 48° 128° 32°

fomenos

Answer:

m<NQS = 32°

Step-by-step explanation:

Given:

m<BQS = 80°

m<BQN = 48°

Required:

m<NQS

SOLUTION:

Angle BQN and angle NQS are adjacent angles having a common line, QN, and a common corner point, Q.

Therefore:

m<BQN + m<NQS = m<BQS (angle addition postulate)

48° + m<NQS = 80° (substitution)

m<NQS = 80 - 48° (Subtraction of 48 from each side)

m<NQS = 32°

3 0

3 years ago

Read 2 more answers

Area and Circumference of Circles

Thepotemich [5.8K]

Pi( $\pi$ ) is the ratio of circumference to diameter for any circle.

Perimeter is the distance around a circle.

Circumference of circle $C = \pi d$ .

Perimeter of circle $= 2 \pi r$

What is circle ?

A circle is a spherical shape without boundaries or edges.

A circle is a closed, curved object with two dimensions in geometry.

Consider two small arcs AB and CD of two circles of radii x and y units, both of which make an angle of measure θ at the centers P and Q respectively.

For smaller values of θ, the arc length AB is almost equal to the length of the line segment $\bar{AB}$ . Similarly, arc CD ≅ $\bar{CD}$ .

Using the SAS rule of triangle similarity, we can say that APB and CQD are similar triangles because their angles are the same and their ratios are AP: PB = CQ: QD = 1: 1. So, it stands to reason that AB: AP = CD: CQ.

Circumference = $\pi \times$ diameter or circumference = 2 $\pi \times$ radius if this constant equals some value.