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Kay [80]
3 years ago
6

A marathon runner completes a 42km course at an average speed of 7km/h. Calculate the time taken to complete the course.

Mathematics
1 answer:
Flura [38]3 years ago
6 0

Answer:

t = 6 hours

Step-by-step explanation:

Given that,

Average speed, v = 7 km/h

Distance, d = 42 km

We need to find the time taken to complete the course. The average speed is given by :

v=\dfrac{d}{t}\\\\or\\\\t=\dfrac{d}{v}\\\\t=\dfrac{42\ km}{7\ km/h}\\\\t=6\ h

So, the time taken to complete the course is 6 hours.

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Alex_Xolod [135]

Answer:

180 cards

Step-by-step explanation:

45x 4= 180

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2 years ago
Where will her cut be located? Round to the nearest tenth. x = (StartFraction m Over m + n EndFraction) (x 2 minus x 1) + x 1 A
Arte-miy333 [17]

Answer:

The correct answer is 25.2 in.

Step-by-step explanation:

It is given that number line goes from 0 to 60 which can be used to represent a ribbon of length = 60 inches.

2 inches of the ribbon are frayed so actual length = 58 inches

Please refer to the attached image for the ribbon.

A is at 0

C is at 60

B is at 2

P is the point to divide the remaining ribbon in the ratio 2:3.

Part AB of the ribbon is frayed.

BP: PC = 2:3

Let BP = 2x and PC = 3x

Now, BP + PC = BC = 58 = 2x + 3x = 5x

So,

5x =58\\\Rightarrow x =11.6

BP = 2\times x = 2 \times 11.6 = 23.2\ inches

Location of the Cut = 2 + 23.2 = <em>25.2 inches</em>

<em></em>

Alternatively, we can use the formula directly:

x = \dfrac{m} {m + n } (x_2 - x_1) + x_1

x_1 = 2\\x_2 = 60

m: n is the ratio 2:3

x = \dfrac{2} {2 +3 } (60- 2) + 2\\\Rightarrow 0.4 (58 )+2\\\Rightarrow 23.2+2 \\\Rightarrow \bold{25.2\ inches}

5 0
4 years ago
Read 2 more answers
I have 3 questions can you answer them?
Kaylis [27]

73 divided by 8967:

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Maru [420]

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Sec^2x-2secx.cosx+cos^2x=tan^2x-sin^2x<br><br> Prove the identity
alexdok [17]

Hello.

sin²x + cos²x = 1

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sec²x = tan²x + 1

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2 years ago
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