Full Question
A 10 kilogram object suspended from the end of a vertically hanging spring stretches the spring 9.8 centimeters. At time t = 0, the resulting mass—spring system is disturbed from its rest state by the force F (t) = 20 cos(8t). The force F (t) is expressed in Newtons and is positive in the downward direction, and time is measured in seconds.
Determine the spring constant k.
Answer:
Spring Constant = 1000Nm^-1
Step-by-step explanation:
Given
Mass = 10kg
Spring Extension = 9.8cm
Spring Constant K = Force/Extension
Force = Mass * Acceleration
Force = 10 * 9.8 = 9.8N
Spring Extension = 9.8 cm = 9.8 /100 = 0.098 m
Spring constant = 98 / 0.098
Spring Constant = 1000Nm^-1
Answer:
y= -2x+23
Step-by-step explanation:
Subtract 2x over
Id say the first one because the points just touch down
Answer:
it is a polynomial because it has more than two terms
Answer:
5/12 - 4/5 = -23/60. You can't simplify -23/60. Hope this is right
Step-by-step explanation:
4/5= 48/60
5/12 = 25/60
25/60-48/60= -23/60
