If the diameter of the smaller circle is 3.5cm, that means the radius is 1.75cm.The area of the smaller circle is π × 1.75², which is ≈ 9.62112750162.
The diameter of the larger circle is 12.5 cm, so the radius would be half that, which is 6.25cm. The area of the larger circle would be π × 6.25², which is ≈ 122.718463031.
So now that we know the area of the larger circle and the smaller circle, we can find the area of the shaded region by subtracting the area of the smaller circle from the area of the larger circle, which is basically just 122.718463031 - 9.62112750162, which is = 113.097336. The closest answer here is 113.04, hence the answer is 113.04cm².
This graph has a horizontal asymptote so it is an exponential graph. It also passes through two points (0,-2) and (1,3). The horizontal asymptote is at y=-3.
The unchanged exponential equation is y=a(b)^x +k
For exponential equations, k is always equal to the horizontal asymptote, so k=-3.
You can check this with the ordered pair (0,-2). After that plug in the other ordered pair, (1,3).
This gives you 3=a(b)^1 or 3=ab. If you know the base the answer is simple as you just solve for a.
If you don't know the base at this point you have to sort of guess. For example, let's say both a and b are whole numbers. In that case b would have to be 3, as it can't be 1 since then the answer never changes, and a is 1. Then choose an x-value and not exact corresponding y-value. In this case x=-1 and y= a bit less than -2.75. Plug in the values to your "final" equation of y=(3)^x -3.
So -2.75=(3^-1)-3.
3^-1 is 1/3, 1/3-3 is -8/3 or -2.6667 which is pretty close to -2.75. So we can say the final equation is y=3^x -3.
Hope this helps! It's a lot easier to solve problems like these given either more points which you can use system of equations with, or with a given base or slope.
Answer:
x=10
Step-by-step explanation:
3x-5x+5.6=-14.4
Simplify
-2x+5.6=-14.4
Subtract 5.6 from both sides
-2x=-20
Divide both sides by -2
x=10
Answer:Commutative
Step-by-step explanation:do the equation backwards