Answer:
x = ±8.43 (to 3sf)
Step-by-step explanation:
Let this number be x.
x² + 10 = 81
x² = 81 - 10
= 71
x = ±√71
= ±8.43 (to 3sf)
A.

- Relative maximum at x = -1.5. Relative minimum at x = 2.5. Point of inflection at x = 0.5.
B.

- Absolute maximum at x = -1.5. Absolute minimum at x = 2.5. This applies for the interval [-4, 5].
C.

- Absolute maximum at x = 0. Absolute minimum at x = 2.5. This applies for the interval [0, 3].
D.

- Test:

- Increasing:
![[-\infty,-1.5)(2.5,\infty]](https://tex.z-dn.net/?f=%5B-%5Cinfty%2C-1.5%29%282.5%2C%5Cinfty%5D)
- Decreasing:

E.

- Concave up:
![(0.5,\infty]](https://tex.z-dn.net/?f=%280.5%2C%5Cinfty%5D)
- Concave down:
A=g
v=⌠g dt
v=gt+C, where C=v initial
v=gt+vi
h=⌠v dt
h=gt^2/2+vit+C, where C=h initial
h=gt^2/2+vit+hi
We are told that vi=42 ft/s, hi=0, and we know g≈-32 ft/s^2 so
h(t)=-16t^2+42t
The ball will hit the ground when h=0 so
-16t^2+42t=0
-2t(8t-21)=0, since t>0
8t-21=0
8t=21
t=21/8
t=2.625 sec
t≈2.6 sec (to nearest tenth of a second)
Answer:
The correct option is 2.
Step-by-step explanation:
The given inequalities are
.... (1)
.... (2)
Solve each inequality.
Subtract 10 from each side of inequality (1).


Divide both the sides by 2.

The value of x is more than 20.
Subtract 10 from each side of inequality (2).


Divide both the sides by 2.

The value of x is less than 50.
Since x > 20 and x < 50, therefore Malcolm needs to consume more than 20 grams of carbohydrates, but less than 50 grams of carbohydrates.
Hence the correct option is 2.
Answer:
28 degrees
Step-by-step explanation:
152 is the exact same measure as angle 2.
To get to 180 you have to add 152 + angle 1
Angle one is the same as angle 3.
180 - 152 = 28
Hope this helps