Answer:
Step-by-step explanation:
The given equations are:
-9.5x – 2.5y = –4.3 (1)
and 7x + 2.5y = 0.8 (2)
Adding equation (1) and (2) together, we get
-9.5x-2.5y+7x+2.5y=-4.3+0.8
⇒-2.5x=-3.5
⇒x=1.4
Now, substitute the value of x=1.4 in equation (1),
-9.5(1.4)-2.5y=-4.3
⇒-13.3-2.5y=-4.3
⇒-13.3+4.3=2.5y
⇒-9=2.5y
⇒y=-3.6
Thus, the value of x and y are 1.4 and -3.6 respectively.
Answer:
x = -4; y = -3
Step-by-step explanation:
2x - 5y = 7
3x - y = -9
Rewrite top equation. Multiply both sides of bottom equation by -5. Add equations. This eliminates y, and we solve for x.
2x - 5y = 7
(+) -15x + 5y = 45
----------------------------
-13x = 52
Divide both sides by -13.
x = -4
Substitute -4 for x in the first original equation and solve for y.
2x - 5y = 7
2(-4) - 5y = 7
-8 - 5y = 7
-5y = 15
y = -3
Answer: x = -4; y = -3
-5 =
Answer:
is it A?
Step-by-step explanation:
I think it's A because no one has answered!
Answer:
-189.8 J
Step-by-step explanation:
We are given that f
Force applied=F=35 Ni-37 Nj
Displacement, s=(-8.7m)i-(3.1m)j
We have to find the work done .
We know that
Work done=
Using the formula
Work done=
Work done=
Using 
Work done=-189.8J
Hence, the work done =-189.8 J
Answer:
<h2>36.14 pounds of 34% copper alloy and 9.86 pounds of 48% copper alloy</h2>
Step-by-step explanation:
First alloy contains 34% copper and the second alloy contains 48% alloy.
We wish to make 46 pounds of a third alloy containing 37% copper.
Let the weight of first alloy used be
in pounds and the weight of second alloy used be
in pounds.
Total weight =

Total weight of copper = 

Subtracting 34 times first equation from second equation,

∴ 36.14 pounds of first alloy and 9.86 pounds of second alloy were used.