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gayaneshka [121]
3 years ago
13

A certain factory produces and sells x kilograms of ice cream per month. It cost c dollars to produce one kilogram of ice cream,

which is then sold for 0.16 dollars. The factory's monthly net profit is P dollars. Write an equation that relates x,c and P
Mathematics
2 answers:
Marina86 [1]3 years ago
8 0

Answer:

P=0.16x-c

............

Ivanshal [37]3 years ago
4 0

Answer:

Khan Academy x(0.16-c)=P

Step-by-step explanation:

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Which of the following statements is true about completing a square? A. When completing the square, subtract the square of half
Darina [25.2K]

Answer:

D

Step-by-step explanation:

So, let's say that we have the following equation:

x^2+bx=0

And we want to complete the square.

What we need to do is to divide the coefficient of x by half. Square that. Then add that number to both sides.

The answer that reflects this is choice D.

For instance if we have:

x^2+4x=0

Divide 4 by 2 and then square it.

4/2 is 2. 2²=4. Add 4 to both sides. Thus:  

(x^2+4x)+4=0+4

And now, we can complete the square:

(x+2)^2=4

5 0
3 years ago
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TWO questions! PLEASE HELP ME!
Mariulka [41]

Answer:

The first one is C I don't know the second one though

Step-by-step explanation:

8 0
3 years ago
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A college student completed some courses worth 3 credits and some courses worth 4 credits. The student earned a total of 59 cred
quester [9]

Answer:

He completed 13 courses worth 3 credits and 5 courses worth 4 credits.

Step-by-step explanation:

Let

Number of courses worth 3 credits = x

Number of courses worth 4 credits = y

1. The student completed a total of 18 courses, then

x+y=18

2. The student earned a total of 59 credits, he earned 3x on 3 credits' courses and 4y on 4 credits' courses, so

3x+4y=59

3. You get the system of two equations:

\left\{\begin{array}{l}x+y=18\\ \\3x+4y=59\end{array}\right.

From the first equation

x=18-y

Substitute it into the second equation:

3(18-y)+4y=59\\ \\54-3y+4y=59\\ \\4y-3y=59-54\\ \\y=5\\ \\x=18-5=13

He completed 13 courses worth 3 credits and 5 courses worth 4 credits.

6 0
3 years ago
HELP ASAP PLZ i need help !<br>help me :((
kodGreya [7K]

Answer:

(1) g[f(x)]=\frac{8x-1}{12x-4}

(2)  g^{-1}(x)=\frac{x+1}{(3x-2)}

(3)    x=\frac{9+\sqrt{129} }{6},  \frac{9-\sqrt{129} }{6}

Step-by-step explanation:

Given functions f(x) = (4x-1)

are                     g(x)=\frac{2x+1}{3x-1}

(1)  g[f(x)]=\frac{2(4x-1)+1}{3(4x-1)-1}

                =\frac{8x-2+1}{12x-3-1}

                =\frac{8x-1}{12x-4}

(2) for g^{-1}(x), rewrite the function g(x) in terms of an equation

y=\frac{2x+1}{3x-1}

Substitute y in place of x and x in place of y, then solve for y.

x=\frac{2y+1}{3y-1}

(3y-1)x = 2y+1

3xy - x = 2y + 1

3xy - 2y = x + 1

y(3x-2) = x + 1

y=(\frac{x+1}{3x-2} )

⇒ g^{-1}(x)=\frac{x+1}{(3x-2)}

(3)    f[g(x)]=(x-1)

       f[g(x)]=4[\frac{2x+1}{3x-1}] =(x-1)

⇒    \frac{(8x+4)-(3x-1)}{3x-1}=(x-1)

⇒    \frac{8x-3x+4+1}{3x-1}=(x-1)

⇒    \frac{5x+5}{(3x-1)}=(x-1)

⇒    5x+5=(3x-1)(x-1)

⇒    5x+5=3x^2-3x-x+1

⇒   5x+5=3x^2-4x+1

⇒   3x^2-9x-4=0

⇒    x=\frac{9\pm\sqrt{(-9)^2-4(-4)\times3} }{2\times3}

   x=\frac{9\pm\sqrt{81+48} }{6}

   x=\frac{9\pm\sqrt{129} }{6}

   x=\frac{9+\sqrt{129} }{6},  \frac{9-\sqrt{129} }{6}

4 0
3 years ago
Subtract: (7x2 + 2x – 3) – (4x2 – 3x + 1)
Cloud [144]

Answer:    3x2+5x−4

The 2 behind 3x is an exponent

7 0
3 years ago
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