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3 years ago

Help quickly!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics

2 answers:

Zielflug [23.3K]3 years ago

4 0

Answer:

option D

Step-by-step explanation:

the value of x = 68

plz mark my answer as brainlist plzzzz .

hope this will be helpful to you .

jok3333 [9.3K]3 years ago

3 0

Answer:

x=68

Step-by-step explanation:

22+x=90 90-22/68

x=68

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Find the indefinite integral using the substitution x = 10 sin(θ). (Use C for the constant of integration.) 1 (100 − x2)3/2 dx

soldi70 [24.7K]

Answer:

The indefinite integral

= $\frac{1}{100}$ ˣ $\frac{x}{\sqrt{100-x^{2} } }$ ⁺ C

Step-by-step explanation:

x= 10sinθ

dx = 10cosθdθ

the step-to-step explanation is in the attachment

3 0

3 years ago

ALGEBRA

Dafna11 [192]

Answer: $g(x)=\frac{1}{2}f(x)$

Step-by-step explanation:

We see that g(x) is a straight line that passes through the origin, just like f(x), so g(x)=kx for some constant k.

Since g(x) passes through (4,2), we know that 2=4k, and thus k=1/2.

So, $\boxed{g(x)=\frac{1}{2}f(x)}$

3 0

2 years ago

(problem 6.13 page 97) Consider a population in which 80% of males and 60% of females are employed. In this population, 55% of i

svp [43]

Answer:

There is a 50.77% probability that no more than one of those chosen is not employed.

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they will be employed, or they will not. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

We have these following percentages:

55% of the individuals are female.

So 45% of the individuals are male.

80% of males are employed. So 20% of males are unemployed.

60% of females are employed. So 40% of females are unemployed.

If I pick five persons at random from this population, what is the probability that no more than one of those chosen is not employed?

Using the binomial distribution, p is the probability that a person is unemployed. 40% of the females and 20% of the males are unemployed. The population is 55% females and 45% males. So

$p = 0.4*0.55 + 0.2*0.45 = 0.31$

There are five persons, so $n = 5$

What is the probability that no more than one of those chosen is not employed?

$P(X \leq 1) = P(X = 0) + P(X = 1)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{5,0}.(0.31)^{0}.(0.69)^{5} = 0.1564$

$P(X = 1) = C_{5,1}.(0.31)^{1}.(0.69)^{4} = 0.3513$

Then

$P(X \leq 1) = P(X = 0) + P(X = 1) = 0.1564 + 0.3513 = 0.5077$

There is a 50.77% probability that no more than one of those chosen is not employed.

7 0

3 years ago

HELP ASAP PLEASE ONLY #4,6,8,10,12,14,16

ExtremeBDS [4]

Answer:

Step-by-step explanation:

Oof, all 6? That's not fun.

I'm going to show you one for the first bunch, (4-12) and hopefully you can get the rest. If not let me know and I can more carefully work you through some others on here.

4) So first we need the angle. How do we find that? Well, we know it's somewhere between 270 and 360 degrees (or 3pi/2 and 2pi radians) since it's in the fourth quadrant. The method to finding the angle is ifferent for each quadrant, but it's nice to know around where you'll get. Anyway,, if we take 360 and subtract that little space that is unlabeled we will know the rest. Hopefully that makes sense, but let me know if not, it's important to understand. Maybe think of what happens if you add the two together, you get around the whole circle then.

Anyway, to find that little sliver, we are going to construct a right triangle wherethe x axis is one side. If you draw a line connecting point p and the x axis you have this right triangle. I am going to call this sliver we don't know s. ANyway, now we use trig here.

s = arcsin(3/5) (you can find 5 pretty easily but let me know if you don't see it.)

You may think to use -3 instead of 3, and it wouldn't be a huge mistake, it will just give you the negative version of what we want.

Anyway, now we know theta is 360-s (or 2pi-s). You can solve s or leave it as arcsin(3/5) so you don't have to round.

Now we can solve the trig functions. If you don't know the sum and difference trig identities you will have to round. They are pretty simple formula though. For instance, sin(2pi - arcsin(3/5)) = sin(2pi)cos(arcsin(3/5))-cos(2pi)sin(arcsin(3/5)) = 0 - 3/5 = -3/5 You will also want to know that s = arcsin(3/5) = arccos(4/5) = arctan(3/4). ROunding will get you close but not exact.

Again, let me know ifyou need any more help, they should just be a lot of doing the same thing over and over and over again though.

14) For 14 and 16 you just need to know how the graphs of sin, cos and tan look. Is this something you have trouble with? Like could you draw the graphs at the intervals of increasing/ decrasing and all. if not I can give a quick explanation.

7 0

3 years ago

Find the area of the figure.

zhuklara [117]

Length x Width x height
14•10•10= 1400

5 0

3 years ago